|
1 |
| -'''Solutions to 6.3.1 Examples of Normal Distributions''' |
| 1 | +"""Solution to the Examples in Section 6.3.1""" |
2 | 2 |
|
3 |
| -# author: Thomas Haslwanter, date: Oct-2015 |
| 3 | +# author: Thomas Haslwanter |
| 4 | +# date: Sept-2019 |
4 | 5 |
|
5 |
| -# Import standard packages |
| 6 | +# Import the required packages |
6 | 7 | import numpy as np
|
7 | 8 | from scipy import stats
|
8 | 9 |
|
9 |
| -# Example 1 |
10 |
| -nd = stats.norm(175, 6) |
11 |
| -p = nd.cdf(184) - nd.cdf(183) |
12 |
| -print('The probability that a randomly selected man is 183 cm tall is {0:.1f}% .'.format(p*100)) |
13 | 10 |
|
14 |
| -# Example 2 |
| 11 | +def man_183(): |
| 12 | + """If cans are assumed to have a standard deviation of 4 g, what does the average |
| 13 | + weight need to be in order to ensure that 99 % of all cans have a weight of at least |
| 14 | + 250 g? |
15 | 15 |
|
16 |
| -# Example 3 |
| 16 | + To answer that question, we calculate the probability that the size is |
| 17 | + between 183.0 and 184.0 cm.""" |
| 18 | + |
| 19 | + # Define the distribution |
| 20 | + mean = 175 |
| 21 | + sd = 6 |
| 22 | + nd = stats.norm(mean, sd) |
| 23 | + |
| 24 | + # Calculate and show the probability |
| 25 | + prob_183 = 100*(nd.cdf(184) - nd.cdf(183)) |
| 26 | + print(f'The probability that a man is exactly 183 cm tall is {prob_183:4.1f} %') |
| 27 | + |
| 28 | + # Note that here I use "f-strings", which only have become available in Python 3.7. |
| 29 | + # For Python 3.6 or earlier, you have to use: |
| 30 | + # print('The probability that a man is exactly 183 cm tall is {0:4.1f} %'.format(prob_183)) |
| 31 | + |
| 32 | + |
| 33 | +def weight_cans(): |
| 34 | + """If cans are assumed to have a standard deviation of 4 g, what does the average |
| 35 | + weight need to be in order to ensure that 99 % of all cans have a weight of at least |
| 36 | + 250 g? """ |
| 37 | + |
| 38 | + # Define the parameters |
| 39 | + sd = 4 |
| 40 | + lower_lim = 250 |
| 41 | + nd = stats.norm() |
| 42 | + |
| 43 | + # Calculate the average weight, and show the result |
| 44 | + mean = lower_lim + sd * nd.ppf(0.99) |
| 45 | + print(f'If the average can weighs {mean:4.1f} g and the standard ' + |
| 46 | + f'deviation is {sd} g, then 99% will weigh above {lower_lim} g.') |
| 47 | + |
| 48 | + |
| 49 | +def small_men(): |
| 50 | + """ If cans are assumed to have a standard deviation of 4 g, what does the average |
| 51 | + weight need to be in order to ensure that 99 % of all cans have a weight of at least |
| 52 | + 250 g? |
| 53 | + """ |
| 54 | + |
| 55 | + # Define the parameters |
| 56 | + male = {'avg':175, 'sd':6} |
| 57 | + female = {'avg':168, 'sd':3} |
| 58 | + |
| 59 | + # Calculate the distribution for the difference between a randomly selected man, and a randomly selected woman |
| 60 | + diff = {'avg':male['avg'] - female['avg'], 'sd': np.sqrt(male['sd']**2 + female['sd']**2)} |
| 61 | + nd = stats.norm(diff['avg'], diff['sd']) |
| 62 | + p_small_male = nd.cdf(0) |
| 63 | + |
| 64 | + # Show the likelyhood that the man is smaller |
| 65 | + print(f'The probability that a randomly selected man is shorter than a randomly selected woman is {p_small_male*100:4.1f}%.') |
| 66 | + |
| 67 | + |
| 68 | +if __name__ == '__main__': |
| 69 | + """Run the individual solutions""" |
| 70 | + man_183() |
| 71 | + weight_cans() |
| 72 | + small_men() |
| 73 | + |
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