😄update my solutions

Author: xingbofeng

README.md

@@ -1,6 +1,6 @@
 <p align="center"><img width="300" src="https://raw.githubusercontent.com/Ma63d/leetcode-spider/master/img/site-logo.png"></p>
 <p align="center">
-    <img src="https://img.shields.io/badge/Solved/Total(Locked)-17/573(107)-green.svg?style=flat-square" alt="">
+    <img src="https://img.shields.io/badge/Solved/Total(Locked)-17/577(107)-green.svg?style=flat-square" alt="">
     <img src="https://img.shields.io/badge/Hard-0-blue.svg?style=flat-square" alt="">
     <img src="https://img.shields.io/badge/Medium-8-blue.svg?style=flat-square" alt="">
     <img src="https://img.shields.io/badge/Easy-9-blue.svg?style=flat-square" alt="">
@@ -10,7 +10,7 @@
 <p align="center">
     <b>Language: javascript python python3 c++ c</b>
     <br>
-    <b>Last updated: 2017-07-29</b>
+    <b>Last updated: 2017-07-31</b>
     <br><br>
 </p>
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solutions/005.longest-palindromic-substring/post.md

@@ -0,0 +1,5 @@
+这道题是求一个字符串中的最长回文串，方法很简单，就是依次遍历整个字符串，对遍历到的每个字符向左向右搜索，如果左右相等则继续向左向右搜索。寻找回文串。
+
+但是记住，上面的方法只考虑了奇回文串，如`aba`，但是像`abba`这样的偶回文串是没有考虑到的，因此注意要把偶回文串的考虑加上去。
+
+然后对`C++`的字符串`API`更熟悉了一点吧，`substr(startIndex, length)`是求子串的`API`，接受两个参数，第一个参数是开始位置，第二个参数是从开始位置向右的长度。跟`JavaScript`的`slice`方法不同哦……

solutions/007.reverse-integer/post.md

@@ -0,0 +1,5 @@
+这道题是反转正整数，注意需要考虑到越界的情况，`C`的话需要引入头文件`limits.h`，引入后`INT_MIN`和`INT_MAX`代表临界值
+
+这道题声明数字只能用`long long`类型。
+
+解法很简单，循环地模`10`拿到最后一位，然后在返回的`result`变量中依次乘`10`即可。

solutions/result.json

@@ -1 +1 @@
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