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cleaned files, added exam files
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‎exam-practice.sql‎

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USE library;
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-- 1. Wypisz wszystkich członków biblioteki z adresami i info czy jest dzieckiem czy nie i
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-- ilość wypożyczeń w poszczególnych latach i miesiącach.
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SELECT firstname + ' ' + lastname as 'name',
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ISNULL((SELECT TOP 1 'n' FROM juvenile j WHERE m.member_no = j.adult_member_no), 'y') as 'is kid',
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MONTH(out_date) as 'month',
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YEAR(out_date) as 'year',
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COUNT(l.title_no) as 'cnt',
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m.member_no
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FROM member m
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INNER JOIN loanhist l on m.member_no = l.member_no
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GROUP BY m.member_no, firstname + ' ' + lastname, MONTH(out_date), YEAR(out_date)
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USE Northwind
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-- 2. Zamówienia z Freight większym niż AVG danego roku.
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SELECT OrderID,
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Freight,
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(SELECT AVG(Freight)
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FROM Orders o2
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WHERE Year(o2.OrderDate) = YEAR(o.OrderDate)) as 'avg',
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YEAR(OrderDate) as 'year'
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FROM Orders o
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WHERE (SELECT AVG(Freight)
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FROM Orders o2
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WHERE Year(o2.OrderDate) = YEAR(o.OrderDate)) < o.Freight
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-- 3. Klienci, którzy nie zamówili nigdy nic z kategorii 'Seafood' w trzech wersjach.
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USE Northwind
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SELECT CustomerID
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FROM CUSTOMERS
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WHERE CustomerID NOT IN (SELECT C.CustomerID
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FROM Customers C
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LEFT JOIN Orders O on C.CustomerID = O.CustomerID
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LEFT JOIN [Order Details] OD on O.OrderID = OD.OrderID
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LEFT JOIN Products P on OD.ProductID = P.ProductID
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LEFT JOIN Categories C2 on P.CategoryID = C2.CategoryID
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WHERE C2.CategoryName = 'Seafood')
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SELECT CustomerID
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FROM Customers Ci
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WHERE NOT EXISTS(SELECT C.CustomerID
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FROM Customers C
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LEFT JOIN Orders O on C.CustomerID = O.CustomerID
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LEFT JOIN [Order Details] OD on O.OrderID = OD.OrderID
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LEFT JOIN Products P on OD.ProductID = P.ProductID
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LEFT JOIN Categories C2 on P.CategoryID = C2.CategoryID
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WHERE C2.CategoryName = 'Seafood'
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AND Ci.CustomerID = C.CustomerID)
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-- 4. Dla każdego klienta najczęściej zamawianą kategorię w dwóch wersjach.
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USE Northwind
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SELECT CI.CustomerID,
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(SELECT TOP 1 C2.CategoryName
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FROM Customers C
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LEFT JOIN Orders O on C.CustomerID = O.CustomerID
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LEFT JOIN [Order Details] OD on O.OrderID = OD.OrderID
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LEFT JOIN Products P on OD.ProductID = P.ProductID
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LEFT JOIN Categories C2 on P.CategoryID = C2.CategoryID
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WHERE C.CustomerID = CI.CustomerID
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GROUP BY C.CustomerID, C2.CategoryName
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ORDER BY COUNT(P.CategoryID) DESC) as 'best_category'
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FROM Customers CI
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-- 1. Podział na company, year month i suma freight
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SELECT S.CompanyName,
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MONTH(OrderDate),
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YEAR(OrderDate),
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SUM(Freight)
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FROM Shippers S
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LEFT JOIN Orders O on S.ShipperID = O.ShipVia
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GROUP BY S.CompanyName,
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MONTH(OrderDate),
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YEAR(OrderDate)
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-- 2. Wypisać wszystkich czytelników, którzy nigdy nie wypożyczyli książki dane
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-- adresowe i podział czy ta osoba jest dzieckiem (joiny, in, exists)
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USE library
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SELECT DISTINCT m.firstname,
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m.lastname,
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m.member_no,
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ISNULL((SELECT 0 FROM adult a WHERE m.member_no = a.member_no), 1) as 'kid',
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(SELECT street
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FROM juvenile j
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INNER JOIN member mi2 on j.member_no = mi2.member_no
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INNER JOIN adult a on a.member_no = j.adult_member_no
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WHERE j.member_no = m.member_no
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UNION
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SELECT street
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FROM member mi
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INNER JOIN adult a on a.member_no = mi.member_no
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WHERE mi.member_no = m.member_no) as 'address'
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FROM member m
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WHERE m.member_no NOT IN (SELECT l.member_no FROM loanhist l)
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SELECT *
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FROM loanhist
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WHERE member_no = 2
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-- adresy wszystkich memberow w LIBRARY
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SELECT street
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FROM juvenile j
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INNER JOIN member mi2 on j.member_no = mi2.member_no
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INNER JOIN adult a on a.member_no = j.adult_member_no
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WHERE j.member_no = 13
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UNION
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SELECT street
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FROM member mi1
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INNER JOIN adult a on a.member_no = mi1.member_no
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WHERE mi1.member_no = 13
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-- 3. Najczęściej wybierana kategoria w 1997 dla każdego klienta
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USE Northwind;
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SELECT CI.CustomerID,
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(SELECT TOP 1 C2.CategoryName
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FROM Customers C
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LEFT JOIN Orders O on C.CustomerID = O.CustomerID
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LEFT JOIN [Order Details] OD on O.OrderID = OD.OrderID
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LEFT JOIN Products P on OD.ProductID = P.ProductID
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LEFT JOIN Categories C2 on P.CategoryID = C2.CategoryID
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WHERE C.CustomerID = CI.CustomerID
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AND YEAR(O.OrderDate) = 1997
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GROUP BY C.CustomerID, C2.CategoryName
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ORDER BY COUNT(P.CategoryID) DESC)
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FROM Customers CI
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-- 4. Dla każdego czytelnika imię nazwisko, suma książek wypożyczony przez tą osobę i
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-- jej dzieci, który żyje w Arizona ma mieć więcej niż 2 dzieci lub kto żyje w Kalifornii
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-- ma mieć więcej niż 3 dzieci
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USE library
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SELECT a.member_no,
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firstname,
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lastname,
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(SELECT COUNT(*) FROM loanhist l WHERE l.member_no = a.member_no) as 'books_parent',
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(SELECT COUNT(*)
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FROM juvenile j
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INNER JOIN loanhist l2 on j.member_no = l2.member_no
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WHERE j.adult_member_no = a.member_no) as 'books_kids'
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FROM adult a
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LEFT JOIN member m on a.member_no = m.member_no
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WHERE (a.state = 'AZ' AND (SELECT COUNT(*) from juvenile j2 WHERE j2.adult_member_no = a.member_no) > 2)
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OR (a.state = 'CA' AND (SELECT COUNT(*) from juvenile j2 WHERE j2.adult_member_no = a.member_no) > 3)
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-- 1. Jaki był najpopularniejszy autor wśród dzieci w Arizonie w 2001
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SELECT TOP 1 author
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FROM juvenile j
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INNER JOIN loanhist l on j.member_no = l.member_no
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INNER JOIN title t on l.title_no = t.title_no
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WHERE YEAR(l.out_date) = 2001
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GROUP BY author
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ORDER BY COUNT(author) DESC;
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-- 2. Dla każdego dziecka wybierz jego imię nazwisko, adres, imię i nazwisko rodzica i
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-- ilość książek, które oboje przeczytali w 2001
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SELECT m.firstname,
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m.lastname,
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(SELECT street + '' + state
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FROM adult
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INNER JOIN juvenile j2 on adult.member_no = j2.adult_member_no
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WHERE j2.member_no = j.member_no) address,
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(SELECT firstname FROM member WHERE j.adult_member_no = member.member_no) parent,
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(SELECT lastname FROM member WHERE j.adult_member_no = member.member_no) parent2,
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(SELECT COUNT(*) FROM loanhist l WHERE l.member_no = j.member_no AND YEAR(in_date) = 2001) +
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(SELECT COUNT(*) FROM loanhist l where l.member_no = j.adult_member_no AND YEAR(in_date) = 2001) books
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FROM juvenile j
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INNER JOIN member m on j.member_no = m.member_no
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-- 3. Kategorie które w roku 1997 grudzień były obsłużone wyłącznie przez ‘United
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-- Package’
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USE Northwind
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SELECT DISTINCT CategoryName
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FROM Categories
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INNER JOIN Products P on Categories.CategoryID = P.CategoryID
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INNER JOIN [Order Details] [O D] on P.ProductID = [O D].ProductID
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INNER JOIN Orders O on [O D].OrderID = O.OrderID
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INNER JOIN Shippers S2 on O.ShipVia = S2.ShipperID
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WHERE S2.CompanyName = 'United Package'
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AND YEAR(ShippedDate) = 1997
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-- 4. Wybierz klientów, którzy kupili przedmioty wyłącznie z jednej kategorii w marcu
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-- 1997 i wypisz nazwę tej kategorii
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SELECT C.CustomerID,
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(SELECT COUNT(DISTINCT C2.CategoryID)
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FROM Categories C2
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INNER JOIN Products P on C2.CategoryID = P.CategoryID
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INNER JOIN [Order Details] [O D] on P.ProductID = [O D].ProductID
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INNER JOIN Orders O on [O D].OrderID = O.OrderID
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WHERE C.CustomerID = O.CustomerID
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AND (YEAR(OrderDate) = 1997 AND MONTH(OrderDate) = 3)),
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(SELECT TOP 1 C2.CategoryName
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FROM Categories C2
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INNER JOIN Products P on C2.CategoryID = P.CategoryID
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INNER JOIN [Order Details] [O D] on P.ProductID = [O D].ProductID
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INNER JOIN Orders O on [O D].OrderID = O.OrderID
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WHERE C.CustomerID = O.CustomerID
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AND (YEAR(OrderDate) = 1997 AND MONTH(OrderDate) = 3))
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FROM Customers C
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WHERE (SELECT COUNT(DISTINCT C2.CategoryID)
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FROM Categories C2
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INNER JOIN Products P on C2.CategoryID = P.CategoryID
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INNER JOIN [Order Details] [O D] on P.ProductID = [O D].ProductID
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INNER JOIN Orders O on [O D].OrderID = O.OrderID
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WHERE C.CustomerID = O.CustomerID
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AND (YEAR(OrderDate) = 1997 AND MONTH(OrderDate) = 3)) = 1
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-- 1. Wybierz dzieci wraz z adresem, które nie wypożyczyły książek w lipcu 2001
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-- autorstwa ‘Jane Austin
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USE library
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SELECT DISTINCT j.member_no, street, firstname, lastname
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FROM juvenile j
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INNER JOIN adult a on j.adult_member_no = a.member_no
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INNER JOIN member m on m.member_no = j.member_no
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INNER JOIN loanhist l on j.member_no = l.member_no
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WHERE j.member_no NOT IN (SELECT member_no
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FROM loanhist
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INNER JOIN title t on t.title_no = loanhist.title_no
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WHERE YEAR(out_date) = 2001
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AND MONTH(out_date) = 7
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AND author = 'Jane Austin')
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-- 2. Wybierz kategorię, która w danym roku 1997 najwięcej zarobiła, podział na miesiące
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USE Northwind
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SELECT CategoryName,
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MONTH(OrderDate) month,
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SUM(Quantity * [O D].UnitPrice * (1 - Discount))
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FROM Categories
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INNER JOIN Products P on Categories.CategoryID = P.CategoryID
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INNER JOIN [Order Details] [O D] on P.ProductID = [O D].ProductID
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INNER JOIN Orders O on [O D].OrderID = O.OrderID
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WHERE YEAR(OrderDate) = 1997
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GROUP BY CategoryName, MONTH(OrderDate)
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ORDER BY 1 DESC;
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-- 3. Dane pracownika i najczęstszy dostawca pracowników bez podwładnych
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--bez podwladnych
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SELECT EmployeeID
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FROM Employees E
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WHERE NOT EXISTS(SELECT E2.EmployeeID FROM Employees E2 WHERE E2.Reportsto = E.EmployeeID)
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--z podwladnymi
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SELECT EmployeeID
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FROM Employees E
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WHERE EXISTS(SELECT E2.EmployeeID FROM Employees E2 WHERE E2.Reportsto = E.EmployeeID)
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SELECT DISTINCT E.EmployeeID,
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(SELECT TOP 1 Shippers.CompanyName
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FROM Orders
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INNER JOIN Employees E3 on Orders.EmployeeID = E3.EmployeeID
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INNER JOIN Shippers ON Orders.ShipVia = Shippers.ShipperID
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WHERE E3.EmployeeID = E.EmployeeID
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GROUP BY Shippers.CompanyName
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ORDER BY COUNT(ShipVia) DESC) BestShipper
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FROM Employees E
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INNER JOIN Orders O on E.EmployeeID = O.EmployeeID
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WHERE NOT EXISTS(SELECT E2.EmployeeID FROM Employees E2 WHERE E2.Reportsto = E.EmployeeID)
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GROUP BY E.EmployeeID, ShipVia
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-- 4. Wybierz tytuły książek, gdzie ilość wypożyczeń książki jest większa od średniej ilości
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-- wypożyczeń książek tego samego autora.
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USE library
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SELECT title,
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(SELECT COUNT(*) FROM loanhist l2 WHERE l2.title_no = t.title_no),
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(SELECT AVG(cnt)
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FROM (
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SELECT COUNT(title) cnt
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FROM loanhist
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INNER JOIN title ON loanhist.title_no = title.title_no
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WHERE author = t.author
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GROUP BY title
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) as cnts)
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FROM title t
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INNER JOIN loanhist l on t.title_no = l.title_no
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WHERE (SELECT COUNT(*) FROM loanhist l2 WHERE l2.title_no = t.title_no) >
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(SELECT AVG(cnt)
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FROM (
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SELECT COUNT(title) cnt
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FROM loanhist
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INNER JOIN title ON loanhist.title_no = title.title_no
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WHERE author = t.author
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GROUP BY title
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) as cnts)

‎exam.sql‎

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-- Zad 1.
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USE library
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SELECT j.member_no,
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m.firstname,
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m.lastname
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FROM juvenile j
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INNER JOIN loanhist l on j.member_no = l.member_no
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INNER JOIN title t on l.title_no = t.title_no
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INNER JOIN member m on j.member_no = m.member_no
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WHERE YEAR(l.in_date) = 2001
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AND MONTH(l.in_date) = 12
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AND DAY(l.in_date) = 14
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AND title = 'Walking'
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-- Zad 2.
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USE Northwind
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SELECT DISTINCT P.ProductName as 'product name',
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CompanyName as 'company name',
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C.CategoryName as 'category name'
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FROM PRODUCTS P
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INNER JOIN Categories C on P.CategoryID = C.CategoryID
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INNER JOIN [Order Details] on P.ProductID = [Order Details].ProductID
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INNER JOIN Orders O on [Order Details].OrderID = O.OrderID
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INNER JOIN Shippers S on O.ShipVia = S.ShipperID
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WHERE OrderDate NOT BETWEEN '1997-02-20' AND '1997-02-25'
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AND CategoryName = 'Beverages'
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-- Zad 3.
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USE Northwind
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SELECT [imie i naziwsko],
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SUM([ilosc zamowien]) as 'ilosc zamowien',
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SUM([wartosc zamowien]) as 'wartosc zamowien'
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FROM (
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SELECT E.FirstName + ' ' + E.LastName as 'imie i naziwsko',
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ISNULL(SUM((UnitPrice * Quantity * (1 - Discount))) + O.Freight, 0) as 'wartosc zamowien',
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COUNT(O.OrderID) as 'ilosc zamowien'
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FROM Employees E
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LEFT JOIN Orders O
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on E.EmployeeID = O.EmployeeID AND (YEAR(OrderDate) = 1997 AND MONTH(OrderDate) = 2)
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LEFT JOIN [Order Details] OD on O.OrderID = OD.OrderID
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GROUP BY E.FirstName + ' ' + E.LastName, Freight) as main
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GROUP BY [imie i naziwsko]

‎lab1-tpp.sql‎ renamed to ‎lab1-2.sql‎

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‎lab2.sql‎ renamed to ‎lab2-3.sql‎

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‎cw2-koncowe.sql‎ renamed to ‎lab3-4.sql‎

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‎zad-domowe-lab4.sql‎ renamed to ‎lab4-5.sql‎

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‎test.sql‎ renamed to ‎restore-database.sql‎

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RESTORE DATABASE joindb
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FROM DISK = 'C:\Users\WLGS\Desktop\joindb2012.bak'
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WITH REPLACE

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