Skip to content

About the numeric scale of the dicriminator loss #106

@Muming-Zhao

Description

@Muming-Zhao

Dear author,

I was using this code for my project and I found the discriminator loss is further divided by 2. I am not very clear with GAN and could you please help explain why to divide 2?

loss_D1 = loss_D1 / args.iter_size / 2

Thanks a lot!

Metadata

Metadata

Assignees

No one assigned

    Labels

    No labels
    No labels

    Projects

    No projects

    Milestone

    No milestone

    Relationships

    None yet

    Development

    No branches or pull requests

    Issue actions