IF condition operator returns the list of values instead of a single value

[binarycat0]

Describe the bug
If the true_result or the false_result contains a list type value, the IF condition operator returns the list of values instead of a single value.
The number of elements depends on the length of the list.

To Reproduce

import formulas
parser = formulas.Parser()
func = parser.ast('=IF(A1, A2, A3)')[1].compile()

func(True, 1, [1,2,3])  # result is Array([1, 1, 1], dtype=object)
func(False, 1, [1,2,3])  # result is Array([1, 2, 3], dtype=object)

func(True, [1,2,3], 1)  # result is Array([1, 2, 3], dtype=object)
func(False, [1,2,3], 1)  # result is Array([1, 1, 1], dtype=object)

Expected behavior
return single value instead of list

Screenshots
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• OS: [macos Sonoma 14.2.1]
• Module Version [1.2.7]
• Python Version [Python 3.11.9 (main, Apr 26 2024, 16:32:48) [Clang 13.0.0 (clang-1300.0.29.3)]]