fix(parseQuery): use object with null prototype (#286)

Author: kricsleo

src/query.ts

@@ -18,6 +18,12 @@ export type QueryObject = Record<string, QueryValue | QueryValue[]>;
 
 export type ParsedQuery = Record<string, string | string[]>;
 
+const EmptyObject = /* @__PURE__ */ (() => {
+  const C = function () {};
+  C.prototype = Object.create(null);
+  return C;
+})() as unknown as { new (): any };
+
 /**
  * Parses and decodes a query string into an object.
  *
@@ -31,7 +37,7 @@ export type ParsedQuery = Record<string, string | string[]>;
 export function parseQuery<T extends ParsedQuery = ParsedQuery>(
   parametersString = "",
 ): T {
-  const object: ParsedQuery = {};
+  const object: ParsedQuery = new EmptyObject();
   if (parametersString[0] === "?") {
     parametersString = parametersString.slice(1);
   }

test/query.test.ts

@@ -86,6 +86,7 @@ describe("getQuery", () => {
     "http://foo.com/?param=%7B%22a%22:%5B%7B%22obj%22:%5B1,2,3%5D%7D%5D%7D": {
       param: '{"a":[{"obj":[1,2,3]}]}',
     },
+    "http://foo.com/?toString=foo": { toString: "foo" },
   };
 
   for (const t in tests) {