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[ADD] BOJ 2559 수열
- 투 포인터
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acmicpc.net/README.md

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| 47 | [키 큰 사람](https://www.acmicpc.net/problem/11292) | [cpp](source/11292.cpp) | 48 | [좌표 압축](https://www.acmicpc.net/problem/18870) | [cpp](source/18870.cpp) |
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| 49 | [두 수의 합](https://www.acmicpc.net/problem/3273) | [cpp](source/3273.cpp) | 50 | [게으른 백곰](https://www.acmicpc.net/problem/10025) | [cpp](source/10025.cpp) |
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| 51 | [약속](https://www.acmicpc.net/problem/1183) | [cpp](source/1183.cpp) | 52 | [효정과 새 모니터](https://www.acmicpc.net/problem/20949) | [cpp](source/20949.cpp) |
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| 53 | [수열](https://www.acmicpc.net/problem/2559) | [cpp](source/2559.cpp) | | | |
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</details>
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acmicpc.net/source/2559.cpp

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// 2559. 수열
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// 2022.05.01
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// 투 포인터
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#include<iostream>
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#include<algorithm>
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using namespace std;
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int arr[100000];
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int main()
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{
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int n, k;
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cin >> n >> k;
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for (int i = 0; i < n; i++)
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{
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cin >> arr[i];
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}
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int sum = 0;
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int idx = 0;
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int ans = -987654321;
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for (int i = 0; i < n; i++)
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{
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sum += arr[i];
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idx++;
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if (idx == k)
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{
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ans = max(ans, sum);
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// two pointer
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sum -= arr[i - k + 1];
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idx--;
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}
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}
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cout << ans << endl;
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return 0;
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}

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