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✨ matrix diagonal sum
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src/1572-matrix-diagonal-sum/index.js

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var diagonalSum = function (mat) {
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const n = mat.length;
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const mid = Math.floor(n / 2);
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let sum = 0;
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// 逐行遍历,每行前后各经过一个
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for (let i = 0; i < n; i++) {
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sum += mat[i][i] + mat[i][n - 1 - i];
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}
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// 奇数方阵需要去除重复项
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return sum - mat[mid][mid] * (n & 1);
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};

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