Method with variable input without overloading

Author: SedaKunda

Java/Advanced/Varargs.java

@@ -0,0 +1,72 @@
+/*
+You are given a class Solution and its main method in the editor. 
+Your task is to create the class Add and the required methods so that the code prints the sum of the numbers passed to the function add.
+
+Note: Your add method in the Add class must print the sum as given in the Sample Output
+
+Input Format
+There are six lines of input, each containing an integer.
+
+Output Format
+There will be only four lines of output. Each line contains the sum of the integers passed as the parameters to add in the main method.
+*/
+
+import java.io.BufferedReader;
+import java.io.InputStreamReader;
+import java.lang.reflect.Method;
+import java.util.*;
+class Add {
+	public void add (int ... n) {
+		int r = n[0];
+		int sum = 0;
+		for (int i = 0; i < n.length; i++) {
+			sum += n[i];
+			System.out.print(n[i]);
+			if (i<n.length-1) {
+				System.out.print("+");
+			}
+		}
+		System.out.println("=" + sum);
+	}
+}
+public class Varargs {
+	
+
+    public static void main(String[] args) {
+       try{
+			BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
+			int n1=Integer.parseInt(br.readLine());
+			int n2=Integer.parseInt(br.readLine());
+			int n3=Integer.parseInt(br.readLine());
+			int n4=Integer.parseInt(br.readLine());
+			int n5=Integer.parseInt(br.readLine());
+			int n6=Integer.parseInt(br.readLine());
+			Add ob=new Add();
+			ob.add(n1,n2);
+			ob.add(n1,n2,n3);
+			ob.add(n1,n2,n3,n4,n5);	
+			ob.add(n1,n2,n3,n4,n5,n6);
+			Method[] methods=Add.class.getDeclaredMethods();
+			Set<String> set=new HashSet<>();
+			boolean overload=false;
+			for(int i=0;i<methods.length;i++)
+			{
+				if(set.contains(methods[i].getName()))
+				{
+					overload=true;
+					break;
+				}
+				set.add(methods[i].getName());
+				
+			}
+			if(overload)
+			{
+				throw new Exception("Overloading not allowed");
+			}
+			}
+			catch(Exception e)
+			{
+				e.printStackTrace();
+			}
+		}
+}