Create StringSearching.java

Author: SedaKunda

Hard-Level/StringSearching.java

@@ -0,0 +1,50 @@
+/*
+You are given two strings. Determine if the second string is a substring of the first (Do NOT use any substr type library function). The second string may contain an asterisk(*) which should be treated as a regular expression i.e. matches zero or more characters. The asterisk can be escaped by a \ char in which case it should be interpreted as a regular '*' character. To summarize: the strings can contain alphabets, numbers, * and \ characters.
+*/
+
+import java.io.*;
+        public class Main {
+            public static void main (String[] args) throws IOException {
+                File file = new File(args[0]);
+                BufferedReader br = new BufferedReader(new FileReader(file));
+                   String line;
+                   while ((line = br.readLine()) != null) { 
+                	   String[] a = line.split(",");
+                	   String frstw = a[0];
+                	   String lastw = a[1];
+                	   int last = lastw.length();
+                	   boolean b = false;                	   
+                	   if(lastw.contains("*") && !lastw.contains("\\*") && lastw.charAt(last-1)!='*') {
+                		   String[] ast = lastw.split("\\*");
+                		   String fw = ast[0];
+                    	   String lw = ast[1];
+                    	   if (frstw.matches(".*"+fw+".*"+lw+".*")) {
+                			   b = true;
+                		   }
+                	   }
+                	   else if (lastw.charAt(last-1)=='*' && lastw.length()>1) {
+                		   String[] ast = lastw.split("\\*");
+                		   String fw = ast[0];
+                    	   if (frstw.matches(".*"+fw+".+")) {
+                			   b = true;
+                		   }
+                	   }
+                	   else if (lastw.charAt(last-1)=='*' && lastw.length()==1) {
+                		   b = true;
+                	   }
+                	   else if ( lastw.contains("\\*")) {
+                		   lastw = lastw.replace("\\", "");
+                		   if (frstw.contains(lastw)) {
+                			   b = true;
+                		   }
+                	   }
+                	   else {
+                		   if (frstw.contains(lastw)) {
+                			   b = true;
+                		   }        	        	  
+                	   }
+                	   System.out.println(b);
+                   }
+                   br.close();
+            }
+        }