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UnionFind.java
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package DataStructures;
/**
* Union Find / Disjoint Set Union DSU
*
* @author Srinivas Vadige, srinivas.vadige@gmail.com
* @since 10 Jan 2025
*/
public class UnionFind {
public static void main(String[] args) {
}
private int size; // The number of elements in this union find
private int[] sz; // Used to track the size of each of the set / group / component
private int[] id; // id[i] points to the parent of i, if id[i] = i then i is a root node
private int numComponents; // Tracks the number of components (sets / groups) in the union find
public UnionFind(int size) {
if (size <= 0) throw new IllegalArgumentException("Size <= 0 is not allowed");
this.size = numComponents = size;
sz = new int[size];
id = new int[size];
for (int i = 0; i < size; i++) {
id[i] = i; // Link to itself (self root)
sz[i] = 1; // Each component is originally of size one
}
}
public int find(int p) { // Find which component/set 'p' belongs to, takes amortized constant time.
int root = p; // Find the root of the component/set
while (root != id[root]) root = id[root];
// Compress the path leading back to the root.
// Doing this operation is called "path compression"
// and is what gives us amortized time complexity.
while (p != root) {
int next = id[p];
id[p] = root;
p = next;
}
return root;
}
// This is an alternative recursive formulation for the find method
// public int find(int p) {
// if (p == id[p]) return p;
// return id[p] = find(id[p]);
// }
// Return whether or not the elements 'p' and
// 'q' are in the same components/set.
public boolean connected(int p, int q) {
return find(p) == find(q);
}
public int componentSize(int p) { // Return the size of the components/set 'p' belongs to
return sz[find(p)];
}
public int size() { // Return the number of elements in this UnionFind/Disjoint set
return size;
}
public int components() { // Returns the number of remaining components/sets
return numComponents;
}
public void unify(int p, int q) { // Unify the components/sets containing elements 'p' and 'q'
if (connected(p, q)) return; // or root1==root2 => return; These elements are already in the same group!
int root1 = find(p); // Now find the root of each of the components
int root2 = find(q);
if (sz[root1] < sz[root2]) { // Merge smaller component/set into the larger one.
sz[root2] += sz[root1];
id[root1] = root2;
sz[root1] = 0;
} else {
sz[root1] += sz[root2];
id[root2] = root1;
sz[root2] = 0;
}
// Since the roots found are different we know that the
// number of components/sets has decreased by one
numComponents--;
}
}