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| 1 | +/** |
| 2 | + * @author : Piyush Kumar |
| 3 | + * Problem Link : https://leetcode.com/problems/median-of-two-sorted-arrays/ |
| 4 | + */ |
| 5 | + |
| 6 | +class Solution { |
| 7 | + public double findMedianSortedArrays(int[] nums1, int[] nums2) { |
| 8 | + int[] nums; |
| 9 | + double medianValue; |
| 10 | + if (nums1.length == 0) { |
| 11 | + if ((nums2.length) % 2 != 0) { |
| 12 | + medianValue = (double) nums2[((nums2.length + 1) / 2) - 1]; |
| 13 | + }else { |
| 14 | + int mid1 = nums2[(nums2.length / 2)]; |
| 15 | + int mid2 = nums2[(nums2.length / 2) - 1]; |
| 16 | + medianValue = ((double) mid1 + (double) mid2)/2; |
| 17 | + } |
| 18 | + }else if (nums2.length == 0) { |
| 19 | + if ((nums1.length) % 2 != 0) { |
| 20 | + medianValue = (double) nums1[((nums1.length + 1) / 2) - 1]; |
| 21 | + }else { |
| 22 | + int mid1 = nums1[(nums1.length / 2)]; |
| 23 | + int mid2 = nums1[(nums1.length / 2) - 1]; |
| 24 | + medianValue = ((double) mid1 + (double) mid2)/2; |
| 25 | + } |
| 26 | + }else { |
| 27 | + nums = new int[nums1.length + nums2.length]; |
| 28 | + for (int k=0,i=0,j=0 ; k < nums1.length+nums2.length; k++) { |
| 29 | + |
| 30 | + if (i == -1) { |
| 31 | + nums[k] = nums2[j++]; |
| 32 | + }else if (j == -1) { |
| 33 | + nums[k] = nums1[i++]; |
| 34 | + }else if (nums1[i] <= nums2[j]) { |
| 35 | + nums[k] = nums1[i++]; |
| 36 | + if (i == nums1.length) { |
| 37 | + i = -1; |
| 38 | + } |
| 39 | + }else { |
| 40 | + nums[k] = nums2[j++]; |
| 41 | + if (j == nums2.length) { |
| 42 | + j = -1; |
| 43 | + } |
| 44 | + } |
| 45 | + } |
| 46 | + if ((nums.length % 2) != 0) { |
| 47 | + medianValue = (double) nums[((nums.length + 1) / 2) - 1]; |
| 48 | + }else { |
| 49 | + int mid1 = nums[(nums.length / 2)]; |
| 50 | + int mid2 = nums[(nums.length / 2) - 1]; |
| 51 | + medianValue = ((double) mid1 + (double) mid2)/2; |
| 52 | + } |
| 53 | + } |
| 54 | + return medianValue; |
| 55 | + } |
| 56 | +} |
| 57 | + |
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