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| 1 | +// 865. Smallest Subtree with all the Deepest Nodes |
| 2 | +// https://leetcode.com/problems/smallest-subtree-with-all-the-deepest-nodes/ |
| 3 | + |
| 4 | +#include <utility> // for std::pair |
| 5 | + |
| 6 | +// Definition for a binary tree node. |
| 7 | +struct TreeNode { |
| 8 | + int val; |
| 9 | + TreeNode* left; |
| 10 | + TreeNode* right; |
| 11 | + TreeNode() : val(0), left(nullptr), right(nullptr) {} |
| 12 | + TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} |
| 13 | + TreeNode(int x, TreeNode* left, TreeNode* right) |
| 14 | + : val(x), left(left), right(right) {} |
| 15 | +}; |
| 16 | + |
| 17 | +// Based on Editorial's Approach 2: Recursion |
| 18 | +class Solution { |
| 19 | + public: |
| 20 | + TreeNode* subtreeWithAllDeepest(TreeNode* root) { |
| 21 | + return GetDeepest(root).second; |
| 22 | + } |
| 23 | + |
| 24 | + private: |
| 25 | + std::pair<int, TreeNode*> GetDeepest(TreeNode* node) { |
| 26 | + if (node == nullptr) { |
| 27 | + return {0, nullptr}; |
| 28 | + } |
| 29 | + const auto& [left_dist, left_node] = GetDeepest(node->left); |
| 30 | + const auto& [right_dist, right_node] = GetDeepest(node->right); |
| 31 | + if (left_dist > right_dist) { |
| 32 | + return {left_dist + 1, left_node}; |
| 33 | + } |
| 34 | + if (right_dist > left_dist) { |
| 35 | + return {right_dist + 1, right_node}; |
| 36 | + } |
| 37 | + return {left_dist + 1, node}; |
| 38 | + } |
| 39 | +}; |
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