forked from keon/algorithms
-
Notifications
You must be signed in to change notification settings - Fork 0
/
factor_combinations.py
60 lines (54 loc) · 1.08 KB
/
factor_combinations.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
"""
Numbers can be regarded as product of its factors. For example,
8 = 2 x 2 x 2;
= 2 x 4.
Write a function that takes an integer n and return all possible combinations of its factors.
Note:
You may assume that n is always positive.
Factors should be greater than 1 and less than n.
Examples:
input: 1
output:
[]
input: 37
output:
[]
input: 12
output:
[
[2, 6],
[2, 2, 3],
[3, 4]
]
input: 32
output:
[
[2, 16],
[2, 2, 8],
[2, 2, 2, 4],
[2, 2, 2, 2, 2],
[2, 4, 4],
[4, 8]
]
"""
# Iterative:
def getFactors(self, n):
todo, combis = [(n, 2, [])], []
while todo:
n, i, combi = todo.pop()
while i * i <= n:
if n % i == 0:
combis += combi + [i, n/i],
todo += (n/i, i, combi+[i]),
i += 1
return combis
# Recursive:
def getFactors(self, n):
def factor(n, i, combi, combis):
while i * i <= n:
if n % i == 0:
combis += combi + [i, n/i],
factor(n/i, i, combi+[i], combis)
i += 1
return combis
return factor(n, 2, [], [])