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20 | 20 |
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21 | 21 | ## 解法
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22 | 22 |
|
23 |
| -动态规划 |
24 |
| - |
25 | 23 | <!-- 这里可写通用的实现逻辑 -->
|
26 | 24 |
|
| 25 | +**方法一:动态规划** |
| 26 | + |
| 27 | +定义状态 `dp[i]` 表示以 `nums[i]` 结尾的连续子数组的最大和,初始时 `dp[0] = nums[0]`,当 $i\gt 0$ 时,状态转移方程为: |
| 28 | + |
| 29 | +$$ |
| 30 | +dp[i]=\max(dp[i-1],0)+nums[i], i>0 |
| 31 | +$$ |
| 32 | + |
| 33 | +答案为 `dp` 数组中的最大值。 |
| 34 | + |
| 35 | +时间复杂度 $O(n)$,其中 $n$ 表示 `nums` 的长度。 |
| 36 | + |
| 37 | +由于 `dp[i]` 只与 `dp[i-1]` 有关,因此可以使用滚动数组优化空间复杂度,将空间复杂度降低到 $O(1)$。 |
| 38 | + |
27 | 39 | <!-- tabs:start -->
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28 | 40 |
|
29 | 41 | ### **Python3**
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30 | 42 |
|
31 | 43 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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32 | 44 |
|
33 | 45 | ```python
|
| 46 | +class Solution: |
| 47 | + def maxSubArray(self, nums: List[int]) -> int: |
| 48 | + n = len(nums) |
| 49 | + dp = [0] * n |
| 50 | + dp[0] = nums[0] |
| 51 | + for i in range(1, n): |
| 52 | + dp[i] = max(dp[i - 1], 0) + nums[i] |
| 53 | + return max(dp) |
| 54 | +``` |
34 | 55 |
|
35 |
| - |
| 56 | +```python |
| 57 | +class Solution: |
| 58 | + def maxSubArray(self, nums: List[int]) -> int: |
| 59 | + ans = s = -inf |
| 60 | + for v in nums: |
| 61 | + s = max(s, 0) + v |
| 62 | + ans = max(ans, s) |
| 63 | + return ans |
36 | 64 | ```
|
37 | 65 |
|
38 | 66 | ### **Java**
|
39 | 67 |
|
40 | 68 | <!-- 这里可写当前语言的特殊实现逻辑 -->
|
41 | 69 |
|
42 | 70 | ```java
|
| 71 | +class Solution { |
| 72 | + public int maxSubArray(int[] nums) { |
| 73 | + int inf = Integer.MIN_VALUE; |
| 74 | + int ans = inf, s = inf; |
| 75 | + for (int v : nums) { |
| 76 | + s = Math.max(s, 0) + v; |
| 77 | + ans = Math.max(ans, s); |
| 78 | + } |
| 79 | + return ans; |
| 80 | + } |
| 81 | +} |
| 82 | +``` |
43 | 83 |
|
| 84 | +### **C++** |
| 85 | + |
| 86 | +```cpp |
| 87 | +class Solution { |
| 88 | +public: |
| 89 | + int maxSubArray(vector<int>& nums) { |
| 90 | + int n = nums.size(); |
| 91 | + vector<int> dp(n); |
| 92 | + dp[0] = nums[0]; |
| 93 | + int ans = dp[0]; |
| 94 | + for (int i = 1; i < n; ++i) { |
| 95 | + dp[i] = max(dp[i - 1], 0) + nums[i]; |
| 96 | + ans = max(ans, dp[i]); |
| 97 | + } |
| 98 | + return ans; |
| 99 | + } |
| 100 | +}; |
| 101 | +``` |
44 | 102 |
|
| 103 | +```cpp |
| 104 | +class Solution { |
| 105 | +public: |
| 106 | + int maxSubArray(vector<int>& nums) { |
| 107 | + int s = INT_MIN, ans = INT_MIN; |
| 108 | + for (int v : nums) { |
| 109 | + s = max(s, 0) + v; |
| 110 | + ans = max(ans, s); |
| 111 | + } |
| 112 | + return ans; |
| 113 | + } |
| 114 | +}; |
| 115 | +``` |
| 116 | + |
| 117 | +### **Go** |
| 118 | + |
| 119 | +```go |
| 120 | +func maxSubArray(nums []int) int { |
| 121 | + n := len(nums) |
| 122 | + dp := make([]int, n) |
| 123 | + dp[0] = nums[0] |
| 124 | + ans := dp[0] |
| 125 | + for i := 1; i < n; i++ { |
| 126 | + dp[i] = max(dp[i-1], 0) + nums[i] |
| 127 | + ans = max(ans, dp[i]) |
| 128 | + } |
| 129 | + return ans |
| 130 | +} |
| 131 | + |
| 132 | +func max(a, b int) int { |
| 133 | + if a > b { |
| 134 | + return a |
| 135 | + } |
| 136 | + return b |
| 137 | +} |
| 138 | +``` |
| 139 | + |
| 140 | +```go |
| 141 | +func maxSubArray(nums []int) int { |
| 142 | + inf := math.MinInt32 |
| 143 | + ans, s := inf, inf |
| 144 | + for _, v := range nums { |
| 145 | + s = max(s, 0) + v |
| 146 | + ans = max(ans, s) |
| 147 | + } |
| 148 | + return ans |
| 149 | +} |
| 150 | + |
| 151 | +func max(a, b int) int { |
| 152 | + if a > b { |
| 153 | + return a |
| 154 | + } |
| 155 | + return b |
| 156 | +} |
45 | 157 | ```
|
46 | 158 |
|
47 | 159 | ### **JavaScript**
|
|
52 | 164 | * @return {number}
|
53 | 165 | */
|
54 | 166 | var maxSubArray = function (nums) {
|
55 |
| - let dp = [-Infinity]; |
56 |
| - for (let i = 0; i < nums.length; i++) { |
57 |
| - let cur = nums[i]; |
58 |
| - dp[i + 1] = Math.max(dp[i] + cur, cur); |
| 167 | + const n = nums.length; |
| 168 | + const dp = new Array(n).fill(0); |
| 169 | + dp[0] = nums[0]; |
| 170 | + let ans = dp[0]; |
| 171 | + for (let i = 1; i < n; ++i) { |
| 172 | + dp[i] = Math.max(dp[i - 1], 0) + nums[i]; |
| 173 | + ans = Math.max(ans, dp[i]); |
| 174 | + } |
| 175 | + return ans; |
| 176 | +}; |
| 177 | +``` |
| 178 | + |
| 179 | +```js |
| 180 | +/** |
| 181 | + * @param {number[]} nums |
| 182 | + * @return {number} |
| 183 | + */ |
| 184 | +var maxSubArray = function (nums) { |
| 185 | + const inf = -Infinity; |
| 186 | + let s = inf; |
| 187 | + let ans = inf; |
| 188 | + for (const v of nums) { |
| 189 | + s = Math.max(s, 0) + v; |
| 190 | + ans = Math.max(ans, s); |
59 | 191 | }
|
60 |
| - return Math.max(...dp); |
| 192 | + return ans; |
61 | 193 | };
|
62 | 194 | ```
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63 | 195 |
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