Run multiple independent Jobs sequentially

[emilhakobian]

I'm trying to execute multiple jobs sequentially with the following order 1st -> 2nd -> 3rd.
One condition is mandatory: each next job must run after the previous completion.
I've tried chain also an example from chain_test.go, but no success

`func init() {
var j1, j2,j3 countJob
j1.name = "first"
j2.name = "second"
j3.name = "third"

j1.delay = 120 * time.Second
j2.delay = 15 * time.Second
    j3.delay = 10 * time.Second

chain := cron.NewChain(cron.DelayIfStillRunning(cron.DiscardLogger))
wrappedJob1 := chain.Then(&j1)
wrappedJob2 := chain.Then(&j2)
wrappedJob3 := chain.Then(&j3)

c := cron.New(cron.WithChain(cron.DelayIfStillRunning(cron.DefaultLogger)))
c.AddJob("05 11 * * *", wrappedJob1)
c.AddJob("06 11 * * *", wrappedJob2)
c.AddJob("08 11 * * *", wrappedJob2)

c.Start()

}
`