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bpo-36138: Improve docs about converting datetime.timedelta to scalars. #12137

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improve docs about converting datetime.timedelta to scalars
Mar 2, 2019
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bpo-36097: Use only public C-API in the_xxsubinterpreters module (add…
ericsnowcurrently Mar 1, 2019
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improve docs about converting datetime.timedelta to scalars
Mar 2, 2019
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improve docs about converting datetime.timedelta to scalars
Mar 2, 2019
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improve docs about converting datetime.timedelta to scalars
Mar 2, 2019
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Merge branch 'fix-issue-36138' of github.com:0xYasser/cpython into fi…
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Delete 2019-03-02-00-19-56.bpo-36138.YA0x77.rst
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8 changes: 5 additions & 3 deletions Doc/library/datetime.rst
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Expand Up @@ -254,8 +254,9 @@ Supported operations:
| | rounded to the nearest multiple of |
| | timedelta.resolution using round-half-to-even.|
+--------------------------------+-----------------------------------------------+
| ``f = t2 / t3`` | Division (3) of *t2* by *t3*. Returns a |
| | :class:`float` object. |
| ``f = t2 / t3`` | Division (3) of overall duration *t2* by |
| | interval unit *t3*. Returns a :class:`float` |
| | object. |
+--------------------------------+-----------------------------------------------+
| ``t1 = t2 / f or t1 = t2 / i`` | Delta divided by a float or an int. The result|
| | is rounded to the nearest multiple of |
Expand Down Expand Up @@ -351,7 +352,8 @@ Instance methods:
.. method:: timedelta.total_seconds()

Return the total number of seconds contained in the duration. Equivalent to
``td / timedelta(seconds=1)``.
``td / timedelta(seconds=1)``. For interval units other than seconds, use the
division form directly (e.g. ``td / timedelta(microseconds=1)``).

Note that for very large time intervals (greater than 270 years on
most platforms) this method will lose microsecond accuracy.
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1 change: 1 addition & 0 deletions Misc/NEWS.d/next/Documentation/2019-03-02-00-40-57.bpo-36138.yfjNzG.rst
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@@ -0,0 +1 @@
Improve documentation about converting datetime.timedelta to scalars.