Added solution to Leetcode Question - 7 | Reverse Integer

0007/README.md

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+# Reverse Integer
+
+Given a signed 32-bit integer ```x```, return ```x``` with its digits reversed. If reversing ```x``` causes the value to go outside the signed 32-bit integer range ```[-231, 231 - 1]```, then return ```0```.
+
+**Assume the environment does not allow you to store 64-bit integers (signed or unsigned).**
+
+
+## Examples
+
+* Example 1
+```
+Input: x = 123
+Output: 321
+```
+
+* Example 2
+```
+Input: x = -123
+Output: -321
+```
+
+* Example 3
+```
+Input: x = 120
+Output: 21
+```
+
+* Example 4
+```
+Input: x = 0
+Output: 0
+```
+
+## Constraints
+* -231 <= x <= 231 - 1

0007/reverse_integer.py

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+class Solution:
+    def reverse(self, x: int) -> int:
+        val = 0
+        pro = 1 if x>0 else -1
+        x = abs(x)
+        while x:
+            val=val*10+x%10
+            x//=10
+        return val*pro  if (val<=2**31 -1 and val>=-2**31 ) else 0