imakshat47_maxElement.cpp

/*
Mark and Toys

    Input Format
        The first line contains two integers,  and , the number of priced toys and the amount Mark has to spend.
        The next line contains  space-separated integers 

    Constraints
        A toy can't be bought multiple times.

    Output Format
        An integer that denotes the maximum number of toys Mark can buy for his son.

    Sample Input
        7 50
        1 12 5 111 200 1000 10
    
    Sample Output
        4
*/
#include <bits/stdc++.h>

using namespace std;

vector<string> split_string(string);

// Complete the maximumToys function below.
int maximumToys(vector<int> prices, int k)
{
    sort(prices.begin(), prices.end());

    int i = 0;
    while (k)
    {
        if ((k - prices[i]) > 0)
        {
            k -= prices[i];
            ++i;
        }
        else
            break;
    }

    return i;
}

int main()
{
    ofstream fout(getenv("OUTPUT_PATH"));

    string nk_temp;
    getline(cin, nk_temp);

    vector<string> nk = split_string(nk_temp);

    int n = stoi(nk[0]);

    int k = stoi(nk[1]);

    string prices_temp_temp;
    getline(cin, prices_temp_temp);

    vector<string> prices_temp = split_string(prices_temp_temp);

    vector<int> prices(n);

    for (int i = 0; i < n; i++)
    {
        int prices_item = stoi(prices_temp[i]);

        prices[i] = prices_item;
    }

    int result = maximumToys(prices, k);

    fout << result << "\n";

    fout.close();

    return 0;
}

vector<string> split_string(string input_string)
{
    string::iterator new_end = unique(input_string.begin(), input_string.end(), [](const char &x, const char &y) {
        return x == y and x == ' ';
    });

    input_string.erase(new_end, input_string.end());

    while (input_string[input_string.length() - 1] == ' ')
    {
        input_string.pop_back();
    }

    vector<string> splits;
    char delimiter = ' ';

    size_t i = 0;
    size_t pos = input_string.find(delimiter);

    while (pos != string::npos)
    {
        splits.push_back(input_string.substr(i, pos - i));

        i = pos + 1;
        pos = input_string.find(delimiter, i);
    }

    splits.push_back(input_string.substr(i, min(pos, input_string.length()) - i + 1));

    return splits;
}