Python if-else

Task
Given an integer, , perform the following conditional actions:

If  is odd, print Weird
If  is even and in the inclusive range of  to , print Not Weird
If  is even and in the inclusive range of  to , print Weird
If  is even and greater than , print Not Weird
Input Format

A single line containing a positive integer, .

Constraints

Output Format

Print Weird if the number is weird. Otherwise, print Not Weird.

Sample Input 0

3
Sample Output 0

Weird
Explanation 0


 is odd and odd numbers are weird, so print Weird.

Sample Input 1

24
Sample Output 1

Not Weird
Explanation 1


 and  is even, so it is not weird.


Solution :-

#!/bin/python

import math
import os
import random
import re
import sys



if __name__ == '__main__':
    n = int(raw_input().strip())
    if(n%2!=0):
        print("Weird")
    elif(n%2==0 and (n>=2 and n<=5)):
        print("Not Weird")
    elif(n%2==0 and (n>=6 and n<=20)):
        print("Weird")
    else:
        print("Not Weird")