Time: 5111 ms (8.51%), Space: 17.7 MB (88.3%) - LeetHub

Author: park-jihoo

leetcode/Medium/2048-next-greater-numerically-balanced-number/2048-next-greater-numerically-balanced-number.py

@@ -0,0 +1,6 @@
+class Solution:
+    def nextBeautifulNumber(self, n: int) -> int:
+        for i in range(n+1, 1224445):
+            count = Counter(str(i))
+            if all(count[d] == int(d) for d in count):
+                return i