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floating widget #373

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@zmoth

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@zmoth

Sometimes a complex embedded widget will produce a very large node(personally, I think it's ugly). there are also windows that need to be very large, but resize() does not solve our problem, e.g. ImageShowModel.

So I wondered if there could be an option for us to decide if the embedded widget for node actually needs to be embedded in node.
bool widgetEmbeded() const { return true; }

Here I have written a simple example. to show the original node and the modified node.

Before:
The image size I show here is 1082x602, and to see the detail you need to zoom in to quite a large size, and it is cumbersome to manipulate.

image

After:
In this example I don't embed the widget in the node, instead I use a double click on the node to generate the dockwidget. Of course, any window can now call node's embeddedWidget(). If this is the case, I am also able to zoom in and out in the image display, etc.

    connect(
        _scene, &DataFlowGraphicsScene::nodeDoubleClicked, this, [this](QtNodes::NodeId nodeId) {
            QString name = _graphModel->nodeData(nodeId, QtNodes::NodeRole::Type).value<QString>();

            bool isEmbeded =
                _graphModel->nodeData(nodeId, QtNodes::NodeRole::WidgetEmbeded).value<bool>();
            auto w = _graphModel->nodeData(nodeId, QtNodes::NodeRole::Widget).value<QWidget *>();

            if (!isEmbeded && w) {
                QDockWidget *dock = new QDockWidget(name, this);
                dock->setWidget(w);
                this->addDockWidget(Qt::LeftDockWidgetArea, dock);
            }
        });

In addition I can choose whether to embed or not via the bool variable, as there are some very simple widgets that might look better with an embed approach.

image

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