- Leading zeros
0
(i.e., to the left) are meaningless
- Invert a bit
- Examples:
~0 = 1
~1 = 0
~0111 = 1000
~100 = 011
- In Java,
~
inverts anint
and not single bits, so:
int b = 0b10;
~b == 11111111111111111111111111111101
- Results in
1
in each position if the corresponding first bit and second bit are1
, otherwise0
. - Enables to find if a certain bit in a number contains
1
or0
. Can be considered like multiplying all bits. - Examples:
10 & 11 = 10
0011 & 0010 = 0010
- Results in
1
in each position if the corresponding first bit or second bit are1
, otherwise0
. - Enables to set a specific bit to
1
. - Examples:
10 | 11 = 11
0011 | 0010 = 0011
- Exclusive OR – results in
1
in each position if the corresponding first bit or second bit are1
, but not both, otherwise0
. - Enables to compare two bits –
1
means they are different,0
means they are the same. - Can be used to invert selected bits in a register. Any bit can be toggled by XOR-ing it with
1
. - XOR-ing a value against itself yields zero.
- Examples:
0101 ^ 0011 = 0110
0010 ^ 1010 = 1000
- XOR can be used for "backup":
- Calculate
a
andb
's XOR:x = a^b
- If needed, recover
a
:a = b^x
- If needed, recover
b
:b = a^x
- Calculate
- Add
n
0
bits to the right. - A left arithmetic shift by
n
is equivalent to multiplying the number by2^n
. - For example:
10111 << 1 = 101110
- Remove
n
bits from the right (0
or1
). - A right arithmetic shift by
n
is equivalent to dividing by2^n
. - For example:
10010111 >> 1 = 1001011
See also Java section on Bit Arithmetics/Operations and Data Structures code examples for BitSet.
0 = 0
1 = 1
10 = 2
11 = 3
100 = 4
101 = 5
110 = 6
111 = 7
1000 = 8
1001 = 9
1010 = 10
1011 = 11
1100 = 12
1101 = 13
1110 = 14
1111 = 15
10000 = 16
...
10010110
^ ^
| |------- bit 0
|
|-------------- bit 7
Having a 1
in the k
-th bit, means that the decimal number is comprised of 2^k
. For example, for the above number:
2^7 + 2^4 + 2^2 + 2^1 = 150