Filter for output of specific commands

[reknih]

Description: Allow me to filter which command outputs I want to display. Still run all tasks.

Use case: I want to debug a particular task of the set of tasks I run with concurrently and focus on its outputs. At the moment, I solve this by calling npm run dev | grep name-of-task. This works but potentially includes false positives. Additionally, concurrently will not color the task name because it is not directly attached to the terminal.

[gustavohenke]

How does the existing --hide flag work for you?

[amannn]

I have a similar situation. I have two processes and would like to use --hide 1 --raw, so that only the output from the first process is displayed. Unfortunately, --raw seems to ignore any --hide argument.

Would it make sense to support this?

[gustavohenke]

Yes, but note that raw mode implies inheriting stdio, which means no control over the output.

concurrently/src/get-spawn-opts.ts

Line 42 in a61ef39

...(raw && { stdio: 'inherit' as const }),

It might be possible to change it to ignore instead of inherit to support your use case.

[reknih]

How does the existing --hide flag work for you?

It works I guess but I run many tasks, so it's much easier to list the task I want to see instead of every other task.

[wottpal]

Thumbs up for --hide 1 --raw . Did anyone manage to get this working (with colors)?

Update: Found a surprisingly simple solution:

concurrently \"command-1\" \"command-2 > /dev/null 2>&1\" --raw

[gustavohenke]

Hey @wottpal and @amannn, the --hide + --raw flag combo has been fixed by #486. It's not yet released.

[gustavohenke]

☝️ It's been released now.
https://github.com/open-cli-tools/concurrently/releases/tag/v9.0.0