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'buffer.Buffer.prototype.lastIndexOf' results in an abort #32753

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@zyscoder

Description

@zyscoder
  • Version: v12.16.0
  • Platform: Linux vul337 4.15.0-91-generic new design of error handling #92-Ubuntu SMP Fri Feb 28 11:09:48 UTC 2020 x86_64 x86_64 x86_64 GNU/Linux
  • Subsystem: buffer

What steps will reproduce the bug?

Directly run the following code snippet using node:

let buffer = require('buffer');
new buffer.Buffer.prototype.lastIndexOf(1, 'str');

It is worth noting that the following code would not cause this abort:

new  require('buffer').Buffer.prototype.lastIndexOf(1, 'str');

Thus we doubt there may be something wrong in somewhere.

How often does it reproduce? Is there a required condition?

No. This potential bug can always be reproduced.

What is the expected behavior?

This is a misuse of 'buffer.Buffer.prototype.lastIndexOf'. The function should throw an exception or other similar error-reporting stuff rather than crash the whole nodejs process.

What do you see instead?

This is the stack dump produced during abort:

./node[40968]: ../src/node_buffer.cc:1014:void node::Buffer::(anonymous namespace)::IndexOfNumber(const FunctionCallbackInfo<v8::Value> &): Assertion `args[2]->IsNumber()' failed.
 1: 0x13f9b30 node::Abort() [./node]
 2: 0x13f9709  [./node]
 3: 0x13b765e  [./node]
 4: 0x17b379c v8::internal::FunctionCallbackArguments::Call(v8::internal::CallHandlerInfo) [./node]
 5: 0x17b23d5  [./node]
 6: 0x17b1092  [./node]
 7: 0x2717a59  [./node]
[2]    40968 abort      ./node

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