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[To Index](/index.md) | ||
--- | ||
# 284.Peeking Iterator | ||
难度:Medium | ||
> Given an Iterator class interface with methods: `next()` and `hasNext()`, design and implement a PeekingIterator that support the `peek()` operation -- it essentially `peek()` at the element that will be returned by the next call to `next()`. | ||
Example: | ||
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``` | ||
Assume that the iterator is initialized to the beginning of the list: [1,2,3]. | ||
Call next() gets you 1, the first element in the list. | ||
Now you call peek() and it returns 2, the next element. Calling next() after that still return 2. | ||
You call next() the final time and it returns 3, the last element. | ||
Calling hasNext() after that should return false. | ||
``` | ||
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Follow up: How would you extend your design to be generic and work with all types, not just integer? | ||
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We can set a right value stands for next value, a bool stands for hasNext() function. | ||
Codes are as follows: | ||
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``` | ||
// Below is the interface for Iterator, which is already defined for you. | ||
// **DO NOT** modify the interface for Iterator. | ||
class Iterator { | ||
struct Data; | ||
Data* data; | ||
public: | ||
Iterator(const vector<int>& nums); | ||
Iterator(const Iterator& iter); | ||
virtual ~Iterator(); | ||
// Returns the next element in the iteration. | ||
int next(); | ||
// Returns true if the iteration has more elements. | ||
bool hasNext() const; | ||
}; | ||
class PeekingIterator : public Iterator { | ||
int right; | ||
bool flag; | ||
public: | ||
PeekingIterator(const vector<int>& nums) : Iterator(nums) { | ||
// Initialize any member here. | ||
// **DO NOT** save a copy of nums and manipulate it directly. | ||
// You should only use the Iterator interface methods. | ||
flag= Iterator::hasNext(); | ||
right = Iterator::next(); | ||
} | ||
// Returns the next element in the iteration without advancing the iterator. | ||
int peek() { | ||
return right; | ||
} | ||
// hasNext() and next() should behave the same as in the Iterator interface. | ||
// Override them if needed. | ||
int next() { | ||
int cur=right; | ||
flag = Iterator::hasNext(); | ||
if(flag) | ||
{ | ||
right = Iterator::next(); | ||
} | ||
return cur; | ||
} | ||
bool hasNext() const { | ||
return flag; | ||
} | ||
}; | ||
``` | ||
> 执行用时 :8 ms, 在所有 C++ 提交中击败了64.25%的用户 | ||
内存消耗 :9.9 MB, 在所有 C++ 提交中击败了38.30%的用户 |
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