2064.cpp

#include <bits/stdc++.h>

using namespace std;

#define print_op(...) ostream& operator<<(ostream& out, const __VA_ARGS__& u)
template<typename A, typename B> print_op(pair<A, B>) { return out << "(" << u.first << ", " << u.second << ")"; }
template<typename T_container, typename T = typename enable_if<!is_same<T_container, string>::value, typename T_container::value_type>::type> print_op(T_container) { out << "{"; string sep; for (const T &x : u) out << sep << x, sep = ", "; return out << "}"; }
template<typename T> void dbg_out(string s, T x) {cerr << "\033[1;35m" << s << "\033[0;32m = \033[33m" << x << "\033[0m\n";}
template<typename T, typename... Args> void dbg_out(string s, T x, Args... args) {for (int i=0, b=0; i<(int)s.size(); i++) if (s[i] == '(' || s[i] == '{') b++; else
if (s[i] == ')' || s[i] == '}') b--; else if (s[i] == ',' && b == 0) {cerr << "\033[1;35m" << s.substr(0, i) << "\033[0;32m = \033[33m" << x << "\033[31m | "; dbg_out(s.substr(s.find_first_not_of(' ', i + 1)), args...); break;}}
#ifdef LOCAL
#define dbg(...) dbg_out(#__VA_ARGS__, __VA_ARGS__)
#else
#define dbg(...)
#endif

#define ar array
#define ll long long
#define ld long double
#define sz(x) ((int)x.size())
#define rep(i, a, b) for (int i = (int)(a); i < (int)(b); i++) 
#define all(a) (a).begin(), (a).end()

const int MAX_N = 1e5 + 5;
const int MAX_L = 20;
const int MAX_C = 26;
const ll MOD = 1e9 + 7;
const ll INF = 1e9;
const ld EPS = 1e-9;

const int MAX = 1e6 + 5;

long long fact[MAX], inv[MAX];

long long inverse(long long a) {
    int ret = 1, b = MOD - 2;
    while (b > 0) {
        if (b & 1) ret = (ret * a) % MOD;
        a = (a * a) % MOD;
        b >>= 1;
    }
    return ret;
}

long long nCk(int n, int k) {
    if (k < 0 || n < k) return 0;
    return fact[n] * inv[k] % MOD * inv[n - k] % MOD;
}

void preprocess() {
    fact[0] = 1;
    for (int i = 1; i < MAX; i++) fact[i] = fact[i - 1] * i % MOD;
    inv[MAX - 1] = inverse(fact[MAX - 1]);
    for (int i = MAX - 2; i >= 0; i--) inv[i] = inv[i + 1] * (i + 1) % MOD;
}

// Catalan Numbers

void solve(int tc = 0) {
    preprocess();
    int n; cin >> n;
    if (n % 2) {
        cout << 0 << "\n";
    } else {
        n /= 2;
        cout << nCk(2 * n, n) * inverse(n + 1) % MOD << "\n";
    }
}

signed main() {
    ios_base::sync_with_stdio(false); cin.tie(NULL);
    int tc = 1;
    // cin >> tc;
    for (int t = 1; t <= tc; t++) {
        // cout << "Case #" << t << ": ";
        solve(t);
    }
}