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Author: namphamit95

PhamDinhNam_92585_CH03/CaseStudy/Page73_CaseStudy_01.py

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+"""
+Program: Page73_CaseStudy_01.py
+Author: Pham Dinh Nam
+Compute an investment report.
+1. The inputs are starting investment amount number of years interest rate (an integer percent)
+2. The report is displayed in tabular form with a header.
+3. Computations and outputs:
+ for each year compute the interest and add it to the investment print a formatted row of results for that year
+4. The ending investment and interest earned are also displayed.
+"""
+
+# Accept the inputs
+startBalance = float(input("Enter the investment amount: "))
+years = int(input("Enter the number of years: "))
+rate = int(input("Enter the rate as a %: "))
+
+# Convert the rate to a decimal number
+rate = rate / 100
+
+# Initialize the accumulator for the interest
+totalInterest = 0.0
+
+# Display the header for the table
+print("%4s%18s%10s%16s" % ("Year", "Starting balance","Interest", "Ending balance"))
+
+# Compute and display the results for each year
+for year in range(1, years + 1):
+ interest = startBalance * rate
+ endBalance = startBalance + interest
+ print("%4d%18.2f%10.2f%16.2f" % (year, startBalance, interest, endBalance))
+ startBalance = endBalance
+ totalInterest += interest
+
+# Display the totals for the period
+print("Ending balance: $%0.2f" % endBalance)
+print("Total interest earned: $%0.2f" % totalInterest)

PhamDinhNam_92585_CH03/CaseStudy/Page93_CaseStudy_01.py

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+"""
+Program: Page93_CaseStudy_01.py
+Author: Pham Dinh Nam
+
+Compute the square root of a number.
+1. The input is a number.
+2. The outputs are the program's estimate of the square root
+using Newton's method of successive approximations, and
+Python's own estimate using math.sqrt.
+"""
+
+
+import math
+
+# Receive the input number from the user
+x = float(input("Enter a positive number: "))
+
+# Initialize the tolerance and estimate
+tolerance = 0.000001
+estimate = 1.0
+
+# Perform the successive approximations
+while True:
+ estimate = (estimate + x / estimate) / 2
+ difference = abs(x - estimate ** 2)
+ print("estimate = ", estimate)
+ print("difference = ", difference)
+ if difference <= tolerance:
+  break
+
+# Output the result
+print("The program's estimate:", estimate)
+print("Python's estimate: ", math.sqrt(x))

PhamDinhNam_92585_CH03/Exercise/Page70_Exercise_01.py

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+"""
+Author: Pham Dinh Nam
+Date: 02/10/2021
+Problem:
+    Write the outputs of the following loops:
+    a. for count in range(5):
+        print(count + 1, end = " ")
+    b. for count in range(1, 4):
+        print(count, end = " ")
+    c. for count in range(1, 6, 2):
+        print(count, end = " ")
+    d. for count in range(6, 1, –1):
+        print(count, end = " ")
+Solution:
+    a. 1 2 3 4 5
+    b. 1 2 3
+    c. 1 3 5
+    d. 6 5 4 3 2
+"""
+
+

PhamDinhNam_92585_CH03/Exercise/Page70_Exercise_02.py

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+"""
+Author: Pham Dinh Nam
+Date: 02/10/2021
+Problem:
+    Write a loop that prints your name 100 times. Each output should begin on a new line.
+Solution:
+
+"""
+
+name = input("Nhap ten cua ban:")
+for count in range(101):
+    print("My name is", name)
+    print(count)

PhamDinhNam_92585_CH03/Exercise/Page70_Exercise_03.py

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+"""
+Author: Pham Dinh Nam
+Date: 02/10/2021
+Problem:
+    Explain the role of the variable in the header of a for loop.
+Solution:
+    When Python executes the type of for loop just discussed, it counts from 0 to the value of the header’s integer expression minus 1.
+    On each pass through the loop, the header’s variable is bound to the current value of this count.
+"""
+

PhamDinhNam_92585_CH03/Exercise/Page70_Exercise_04.py

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+"""
+Author: Pham Dinh Nam
+Date: 02/10/2021
+Problem:
+    Write a loop that prints the first 128 ASCII values followed by the corresponding characters (see the section on characters in Chapter 2). Be aware that most of the ASCII values in the range “0..31” belong to special control characters with no standard print representation, so you might see strange symbols in the output for these values.
+Solution:
+
+"""
+
+for count in range (130):
+    print("Ky tu so", count, "la", chr(count))
+

PhamDinhNam_92585_CH03/Exercise/Page70_Exercise_05.py

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+"""
+Author: Pham Dinh Nam
+Date: 02/10/2021
+Problem:
+    Assume that the variable teststring refers to a string. Write a loop that prints
+    each character in this string, followed by its ASCII value.
+Solution:
+
+"""
+
+for character in "Hello World":
+ print(ord(character), end = " ")
+
+

PhamDinhNam_92585_CH03/Exercise/Page72_Exercise_01.py

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+"""
+Author: Pham Dinh Nam
+Date: 02/10/2021
+Problem:
+    Assume that the variable amount refers to 24.325. Write the outputs of the following statements:
+     a. print("Your salary is $%0.2f" % amount)
+     b. print("The area is %0.1f" % amount)
+     c. print("%7f" % amount
+Solution:
+    a. Your salary is $24.32
+    b. The area is 24.3
+    c. 24.325000
+"""
+
+amount = 24.325
+
+print("Your salary is $%0.2f" % amount)
+print("The area is %0.1f" % amount)
+print("%7f" % amount)
+
+
+

PhamDinhNam_92585_CH03/Exercise/Page72_Exercise_02.py

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+"""
+Author: Pham Dinh Nam
+Date: 02/10/2021
+Problem:
+    Write a code segment that displays the values of the integers x, y, and z on a single line, such that each value is right-justified with a field width of 6
+Solution:
+
+"""
+
+x = int(input("Nhap X: "))
+y = int(input("Nhap Y: "))
+z = int(input("Nhap Z: "))
+
+# noinspection PyStringFormat
+print("-%6s" % x, y, z)

PhamDinhNam_92585_CH03/Exercise/Page72_Exercise_03.py

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+"""
+Author: Pham Dinh Nam
+Date: 02/10/2021
+Problem:
+    Write a format operation that builds a string for the float variable amount that has exactly two digits of precision and a field width of zero.
+Solution:
+
+"""