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Connecting to kernel for python 3.10.0 failed #8944

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Description

Environment data

  • VS Code version: 1.64.0
  • Jupyter Extension version (available under the Extensions sidebar): v2022.1.1001775990
  • Python Extension version (available under the Extensions sidebar): v2022.0.1786462952
  • OS (Windows | Mac | Linux distro) and version: Mac
  • Python and/or Anaconda version: 3.10.0
  • Type of virtual environment used (N/A | venv | virtualenv | conda | ...): conda 4.11.0
  • Jupyter server running: Local

Expected behaviour

When executing a jupyter notebook python cell, the cell should be executed

Actual behaviour

Connecting to kernel (Python 3.10.0): waiting for jupyter server

This was fine for Jupyter extension v2022.1.1001614873.
This is also fine for python 3.9.
Only failed with python 3.10 and last jupyter extension v2022.1.1001775990

Steps to reproduce:

Create an empty Jupyter notebook.
Type some python code in a cell and try to execute it.

[NOTE: Self-contained, minimal reproducing code samples are extremely helpful and will expedite addressing your issue]

  1. XXX

Logs

Output for Jupyter in the Output panel (ViewOutput, change the drop-down the upper-right of the Output panel to Jupyter)

XXX

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bugIssue identified by VS Code Team member as probable buginfo-neededIssue requires more information from posternotebook-kernelKernels issues (start/restart/switch/execution, install ipykernel)

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