forked from fishercoder1534/Leetcode
-
Notifications
You must be signed in to change notification settings - Fork 0
/
_18.java
65 lines (57 loc) · 1.97 KB
/
_18.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
package com.fishercoder.solutions;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
/**
* 18. 4Sum
*
* Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target?
* Find all unique quadruplets in the array which gives the sum of target.
Note: The solution set must not contain duplicate quadruplets.
For example, given array S = [1, 0, -1, 0, -2, 2], and target = 0.
A solution set is:
[
[-1, 0, 0, 1],
[-2, -1, 1, 2],
[-2, 0, 0, 2]
]*/
public class _18 {
public List<List<Integer>> fourSum(int[] nums, int target) {
List<List<Integer>> result = new ArrayList();
if (nums == null || nums.length == 0) {
return result;
}
Arrays.sort(nums);
for (int i = 0; i < nums.length - 3; i++) {
if (i > 0 && nums[i - 1] == nums[i]) {
continue;
}
for (int j = i + 1; j < nums.length - 2; j++) {
if (j > i + 1 && nums[j - 1] == nums[j]) {
continue;
}
int left = j + 1;
int right = nums.length - 1;
while (left < right) {
int sum = nums[i] + nums[j] + nums[left] + nums[right];
if (sum == target) {
result.add(Arrays.asList(nums[i], nums[j], nums[left], nums[right]));
while (left + 1 < right && nums[left] == nums[left + 1]) {
left++;
}
while (right - 1 > left && nums[right] == nums[right - 1]) {
right--;
}
left++;
right--;
} else if (sum > target) {
right--;
} else {
left++;
}
}
}
}
return result;
}
}