Url should ignore the fullwidth code

[crossle]

fullwith symbol should be ingore, like https://google.com，你好
https://en.wikipedia.org/wiki/Halfwidth_and_fullwidth_forms

[rodneyrehm]

Where should that symbol be ignored specifically?

[crossle]

like （https://www.googoe.com/CN_UST）；it's use fullwidth symbol （ and ）

[rodneyrehm]

To make sure i understood correctly: you'd like URI.withinString() to categorically exclude fullwidth characters (U+FF00 - U+FFEF) from URLs.

This could be achieved by extending URI.findUri.end:

URI.findUri.end = /[\s\r\n]|[\uFF00-\uFFEF]|$/;

var text = "like （https://www.googoe.com/CN_UST）；it's use fullwidth symbol `（ `and` ）`"
  + "\n"
  + "fullwith symbol should be ingore, like https://google.com，你好 "
  + "https://en.wikipedia.org/wiki/Halfwidth_and_fullwidth_forms";

var result = URI.withinString(text, url => {
  console.log('found:', url);
  return '<a>' + url + '</a>';
});

console.log('replaced:', result);

which would output:

found: https://www.googoe.com/CN_UST
found: https://google.com
found: https://en.wikipedia.org/wiki/Halfwidth_and_fullwidth_forms
replaced: like （<a>https://www.googoe.com/CN_UST</a>）；it's use fullwidth symbol `（ `and` ）`
fullwith symbol should be ingore, like <a>https://google.com</a>，你好 <a>https://en.wikipedia.org/wiki/Halfwidth_and_fullwidth_forms</a>

It should be noted that neither github's URL matcher, nor Chrome Dev Tools' URL matcher behaves that way. Both include fullwidth characters. Also, URL accepts fullwidth characters:

var url = new URL("https://www.googoe.com/CN_UST）；it's");
console.log(url.href);
// https://www.googoe.com/CN_UST%EF%BC%89%EF%BC%9Bit's