Merge pull request #1910 from vsmutok/update-readme

Author: sergii-nosachenko

README.md

@@ -1,4 +1,39 @@
 # Count Occurrences
 
 - Read [the guideline](https://github.com/mate-academy/py-task-guideline/blob/main/README.md) before start
-- Implement the task described [here](app/main.py)
+
+## Task Description
+
+You are required to implement the `count_occurrences` function that takes two parameters:
+
+1. **phrase**: A string in which to count occurrences of a letter.
+2. **letter**: The letter whose occurrences need to be counted in the given phrase.
+
+The function should return the number of times the letter appears in the phrase, while being **case insensitive**.
+
+### Examples:
+
+- `count_occurrences("letter", "t")` should return `2`
+- `count_occurrences("abc", "a")` should return `1`
+- `count_occurrences("abc", "d")` should return `0`
+- `count_occurrences("ABC", "a")` should return `1`
+
+### Function Signature:
+
+```python
+def count_occurrences(phrase: str, letter: str) -> int:
+    """
+    Count occurrences of a letter in a phrase (case insensitive).
+
+    :param phrase: The phrase to search within.
+    :param letter: The letter to count occurrences of.
+    :return: The number of occurrences of the letter in the phrase.
+    """
+```
+
+## Guidelines
+
+- The function must be **case insensitive**. This means that both the phrase and the letter should be treated as if they are in the same case (upper or lower).
+  
+- It is **recommended** to avoid using loops to solve this task. Instead, consider utilizing Python's built-in string functions to simplify the solution.
+

app/main.py

@@ -1,17 +1,3 @@
 def count_occurrences(phrase: str, letter: str) -> int:
-    """
-    Implement count_occurrences function:
-
-    It takes a phrase and a letter and calculates the number of times
-    the letter appears in the phrase. The function is case insensitive.
-
-    count_occurrences("letter", "t") == 2
-    count_occurrences("abc", "a") == 1
-    count_occurrences("abc", "d") == 0
-    count_occurrences("ABC", "a") == 1
-
-    :param phrase: phrase to count in it
-    :param letter: letter to find occurrences of it
-    :return: count occurrences of letter in phrase
-    """
     # write your code here
+    pass