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If the .fns contains namespace, it will throw an error.
data.frame(x=1) |>tidytable::mutate.(tidytable::across.(.fns=forcats::as_factor))
#> Error in `fn_to_expr()`:#> ! .fns needs to be a list, function name, or formuladata.frame(x=1) |>dplyr::mutate(dplyr::across(.fns=forcats::as_factor))
#> x#> 1 1
If the
.fns
contains namespace, it will throw an error.Created on 2022-06-24 by the reprex package (v2.0.1)
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