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Algorithms_Dynamic_Programming_02_Subset_Style.cpp
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/*
*
*
******************************************** Licence *******************************************
* *
* This File is part of Algorithms Arabic Video Series *
* Made By Eng Mostafa Saad, Teaching Assistant in FCI - Cairo University *
* *
* Available at My YouTube Channel: http://www.youtube.com/user/nobody123497?feature=mhee *
* *
* Feel free to make use of it at anytime, for any reason, in anyway, without any obligations. *
* *
* *
* In case of finding a mistake, kindly notify me at: mostafa.saad.fci@gmail.com *
* *
* Mostafa Saad Ibrahim © 2013 *
* *
************************************************************************************************
*
*
*/
#include<set>
#include<map>
#include<list>
#include<iomanip>
#include<cmath>
#include<string>
#include<vector>
#include<queue>
#include<stack>
#include<complex>
#include<sstream>
#include<iostream>
#include<fstream>
#include<algorithm>
#include<numeric>
#include<utility>
#include<functional>
#include<stdio.h>
#include<assert.h>
#include<memory.h>
#include<bitset>
using namespace std;
#define all(v) ((v).begin()), ((v).end())
#define sz(v) ((int)((v).size()))
#define clr(v, d) memset(v, d, sizeof(v))
#define rep(i, v) for(int i=0;i<sz(v);++i)
#define lp(i, n) for(int i=0;i<(int)(n);++i)
#define lpi(i, j, n) for(int i=(j);i<(int)(n);++i)
#define lpd(i, j, n) for(int i=(j);i>=(int)(n);--i)
typedef long long ll;
const double EPS = (1e-7);
int dcmp(double x, double y) { return fabs(x-y) <= EPS ? 0 : x < y ? -1 : 1; }
#define pb push_back
#define MP make_pair
#define P(x) cout<<#x<<" = { "<<x<<" }\n"
typedef long double ld;
typedef vector<int> vi;
typedef vector<double> vd;
typedef vector< vi > vvi;
typedef vector< vd > vvd;
typedef vector<string> vs;
// subset DP. 1 2 3 4 5 6
int numList[] = {5, 2, 7, 3, 4, 6}; // solution is finally set of 0s and 1s..pick or leave.
// 0 1 0 1 1 1
int m = 7;
// called with LIS(0, m)
int LIS(int i, int prev)
{
if(i == m)
return 0;
int choice1 = LIS(i+1, prev); // LEAVE
int choice2 = 0;
if(numList[prev] <= numList[i])
choice2 = LIS(i+1, i) + 1;
return max(choice1, choice2);
}
// W: 10, 4 , 20, 5, 7
// P: 10, 15, 3 , 1, 4
// knapsack size = 12
// 0 1 0 0 1
const int MAX = 5;
int n = 5;
int weights[MAX] = {10, 4, 20, 5, 7};
int benfit[MAX] = {10, 15, 3, 1, 4};
// called with knapsack(0, intialWeight)
int knapsack(int i, int reminder) // aka 0/1 knapsack
{
if(i == n)
return 0;
int choice1 = knapsack(i+1, reminder);
int choice2 = 0;
if(reminder >= weights[i])
choice2 = knapsack(i+1, reminder - weights[i]) + benfit[i];
return max(choice1, choice2);
}
string str1 = "abcdefgzh";
string str2 = "ackghefhlmn";
// abcdefgzh
// 101011001
// ackghefhlmn
// 11000111000
// called with LCS(0, 0)
int LCS(int i, int j)
{
if(i == sz(str1) || j == sz(str2))
return 0;
if(str1[i] == str2[j])
return 1 + LCS(i+1, j+1);
int choice1 = LCS(i+1, j);
int choice2 = LCS(i, j+1);
return max(choice1, choice2);
}
int main()
{
cout<<LCS(0, 0);
return 0;
}