readme added

Author: letsdeepchat

ADVANCED SELECT AND JOINS/1731. The Number of Employees Which Report to Each Employee.sql

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+# Write your MySQL query statement below
+SELECT m.employee_id,
+        m.name,
+        count(e.employee_id) AS reports_count,
+        round(avg(e.age)) AS average_age
+FROM
+    employees e JOIN employees m
+ON
+    e.reports_to = m.employee_id
+GROUP BY 
+    employee_id 
+ORDER BY
+    employee_id;