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| 1 | +package leetcode; |
| 2 | + |
| 3 | +import java.util.Arrays; |
| 4 | + |
| 5 | +/** |
| 6 | + * Project Name : Leetcode |
| 7 | + * Package Name : leetcode |
| 8 | + * File Name : RangeSumQueryMutable |
| 9 | + * Creator : Leo |
| 10 | + * Description : 307. Range Sum Query - Mutable |
| 11 | + */ |
| 12 | +public class RangeSumQueryMutable { |
| 13 | + |
| 14 | + int[] nums; |
| 15 | + int[] tree; |
| 16 | + int n; |
| 17 | + |
| 18 | + // time : O(n * logn) |
| 19 | + public RangeSumQueryMutable(int[] nums) { |
| 20 | + n = nums.length; |
| 21 | + tree = new int[n + 1]; |
| 22 | + this.nums = new int[n]; |
| 23 | + for (int i = 0; i < n; i++) { |
| 24 | + update(i, nums[i]); |
| 25 | + } |
| 26 | + } |
| 27 | + |
| 28 | + // time : O(logn) |
| 29 | + public void update(int i, int val) { |
| 30 | + if (n == 0) return; |
| 31 | + int diff = val - nums[i]; |
| 32 | + nums[i] = val; |
| 33 | + for (int j = i + 1; j <= n; j += j & (-j)) { |
| 34 | + tree[j] += diff; |
| 35 | + } |
| 36 | + } |
| 37 | + |
| 38 | + // time : O(logn) |
| 39 | + public int sumRange(int i, int j) { |
| 40 | + return sum(j + 1) - sum(i); |
| 41 | + } |
| 42 | + |
| 43 | + private int sum(int k) { |
| 44 | + int sum = 0; |
| 45 | + for (int i = k; i > 0; i -= i & (-i)) { |
| 46 | + sum += tree[i]; |
| 47 | + } |
| 48 | + return sum; |
| 49 | + } |
| 50 | + |
| 51 | + /** |
| 52 | + * 解法2 |
| 53 | + */ |
| 54 | + //private int[] tree; |
| 55 | + //private int[] nums; |
| 56 | + |
| 57 | + public void NumArray(int[] nums) { |
| 58 | + this.nums = nums; |
| 59 | + int sum; |
| 60 | + int lowbit; |
| 61 | + tree = new int[nums.length + 1]; |
| 62 | + for (int i = 1; i < tree.length; i++) { |
| 63 | + sum = 0; |
| 64 | + lowbit = i & (-i); |
| 65 | + for (int j = i; j > i - lowbit; j--) { |
| 66 | + sum = sum + nums[j - 1]; |
| 67 | + } |
| 68 | + tree[i] = sum; |
| 69 | + } |
| 70 | + } |
| 71 | + |
| 72 | + public void update2(int i, int val) { |
| 73 | + int diff = val - nums[i]; |
| 74 | + nums[i] = val; |
| 75 | + i++; |
| 76 | + for (; i < tree.length; i += (i & (-i))) { |
| 77 | + tree[i] += diff; |
| 78 | + } |
| 79 | + } |
| 80 | + |
| 81 | + public int sumRange2(int i, int j) { |
| 82 | + return sum2(j + 1) - sum2(i); |
| 83 | + } |
| 84 | + |
| 85 | + private int sum2(int k) { |
| 86 | + int sum = 0; |
| 87 | + for (int i = k; i > 0; i -= i & (-i)) { |
| 88 | + sum += tree[i]; |
| 89 | + } |
| 90 | + return sum; |
| 91 | + } |
| 92 | + |
| 93 | +} |
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