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279.perfect-squares
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luzhipeng committed Mar 27, 2019
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38 changes: 0 additions & 38 deletions 279.perfect-squares.js

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104 changes: 104 additions & 0 deletions 279.perfect-squares.md
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## 题目地址
https://leetcode.com/problems/perfect-squares/description/

## 题目描述


```
Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...) which sum to n.
Example 1:
Input: n = 12
Output: 3
Explanation: 12 = 4 + 4 + 4.
Example 2:
Input: n = 13
Output: 2
Explanation: 13 = 4 + 9.
```

## 思路

直接递归处理即可,但是这种暴力的解法很容易超时。如果你把递归的过程化成一棵树的话(其实就是递归树),
可以看出中间有很多重复的计算。

如果能将重复的计算缓存下来,说不定能够解决时间复杂度太高的问题。

> 递归对内存的要求也很高, 如果数字非常大,也会面临爆栈的风险,将递归转化为循环可以解决。
如果使用DP,其实本质上和递归 + 缓存 差不多。

## 关键点解析

- 如果用递归 + 缓存, 缓存的设计很重要
我的做法是key就是n,value是以n为起点,到达底端的深度。
下次取出缓存的时候用当前的level + 存的深度 就是我们想要的level.

## 代码

```js
/*
* @lc app=leetcode id=279 lang=javascript
*
* [279] Perfect Squares
*
* https://leetcode.com/problems/perfect-squares/description/
*
* algorithms
* Medium (40.98%)
* Total Accepted: 168.2K
* Total Submissions: 408.5K
* Testcase Example: '12'
*
* Given a positive integer n, find the least number of perfect square numbers
* (for example, 1, 4, 9, 16, ...) which sum to n.
*
* Example 1:
*
*
* Input: n = 12
* Output: 3
* Explanation: 12 = 4 + 4 + 4.
*
* Example 2:
*
*
* Input: n = 13
* Output: 2
* Explanation: 13 = 4 + 9.
*/

const mapper = {};

function d(n, level) {

if (n === 0) return level;

let i = 1;
const arr = [];

while(n - i * i >= 0) {
const hit = mapper[n - i * i];
if (hit) {
arr.push(hit + level);
} else {
const depth = d(n - i * i, level + 1) - level;
mapper[n - i * i] = depth;
arr.push(depth + level);
}
i++;
}

return Math.min(...arr);
}
/**
* @param {number} n
* @return {number}
*/
var numSquares = function(n) {
return d(n, 0);
};
```
1 change: 1 addition & 0 deletions README.md
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Expand Up @@ -30,6 +30,7 @@ leetcode题解,记录自己的leecode解题之路。
- [328.odd-even-linked-list](./328.odd-even-linked-list.md)
- [445.add-two-numbers-ii](./445.add-two-numbers-ii.md)
- [877.stone-game](./877.stone-game.md)
- [279.perfect-squares](./279.perfect-squares.md)

### 困难难度
- [145.binary-tree-postorder-traversal](./145.binary-tree-postorder-traversal.md)
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