38.py

#-*- coding:utf-8 -*-

"""
Take the number 192 and multiply it by each of 1, 2, and 3:

192 × 1 = 192
192 × 2 = 384
192 × 3 = 576
By concatenating each product we get the 1 to 9 pandigital, 192384576. We will call 192384576 the concatenated product of 192 and (1,2,3)

The same can be achieved by starting with 9 and multiplying by 1, 2, 3, 4, and 5, giving the pandigital, 918273645, which is the concatenated product of 9 and (1,2,3,4,5).

What is the largest 1 to 9 pandigital 9-digit number that can be formed as the concatenated product of an integer with (1,2, ... , n) where n > 1?
"""

def get_pandigital(n):
    pandigital = ''
    for x in xrange(1, 10):
        pandigital += str(n*x)
        if len(pandigital) >= 9:
            break
    if len(pandigital) == 9 and sorted(dict.fromkeys(list(pandigital)).keys()) == list("123456789"):
        return pandigital
    return ''


def main():
    max = 0
    for n in xrange(1, 10000):
        p = get_pandigital(n)
        if p and p > max:
            max = p
    print max


if __name__ == '__main__':
    main()