Added simple calculator code written by me

Coding/simple_calculator.py

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+print("NOTE: You can only perform calculatons on 4 numbers!!")
+def sum(a, b, c = 0, d = 0):
+  return a + b + c + d
+def sub(a, b, c = 0, d = 0):
+  return a - b - c - d
+def mul(a, b, c = 1, d = 1):
+  return a * b * c * d
+def div(a, b, c = 1, d = 1):
+  return a / b / c / d
+def quit():
+  pass
+while True:
+  print("Choose from \'sum\' for addition (+), \'sub\' for subtraction (-), \'mul\' for multiplication (x), \'div\' for division (/) and \'quit\' to quit.")
+  do = eval(input("What do you want to do?: "))
+  if (do == sum or do == sub or do == mul or do == div):
+    z = int(input("Enter the first number: "))
+    y = int(input("Enter the second number: "))
+    a = input("Do you want to add more numbers? (y/n): ")
+    if a == "y":
+      x = int(input("Enter the third number: "))
+      a = input("Do you want to add more numbers? (y/n): ")
+      if a == "y":
+        w = int(input("Enter the fourth number: "))
+        print(f"The result of the numbers is {do(z, y, x, w)}")
+      elif a == 'n':
+        print(f"The result of the numbers is {do(z, y, x)}")
+      else:
+        print("Please enter either 'y' or 'n'.")
+    elif a == 'n':
+      print(f"The result of the numbers is {do(z, y)}")
+    else:
+      print("Please enter either 'y' or 'n'.")
+  elif do == quit:
+    break
+  else:
+    print("Please choose only from the mentioned options.")