Remove Nth Node from the end of a linked list solution

Author: joshguha

18-removeNthNodeFromEndOfList.js

@@ -0,0 +1,53 @@
+/**
+ * Definition for singly-linked list.
+ * function ListNode(val, next) {
+ *     this.val = (val===undefined ? 0 : val)
+ *     this.next = (next===undefined ? null : next)
+ * }
+ */
+/**
+ * @param {ListNode} head
+ * @param {number} n
+ * @return {ListNode}
+ */
+var removeNthFromEnd = function (head, n) {
+    let traverseList = (head) => {
+        if (head === null) {
+            return [];
+        }
+
+        return [head].concat(traverseList(head.next));
+    };
+
+    let arr = traverseList(head);
+    let deleteIndex = arr.length - n;
+    if (deleteIndex === 0) {
+        return arr[1];
+    } else if (deleteIndex > 0) {
+        let prev = arr[deleteIndex - 1];
+        prev.next = arr[deleteIndex + 1];
+        return arr[0];
+    } else {
+        return [];
+    }
+};
+let c = new ListNode(1);
+let b = new ListNode(45, c);
+let a = new ListNode(3, b);
+
+let traverseList = (head) => {
+    if (head === null) {
+        return [];
+    }
+
+    return [head].concat(traverseList(head.next));
+};
+
+function ListNode(val, next) {
+    this.val = val === undefined ? 0 : val;
+    this.next = next === undefined ? null : next;
+}
+
+let arr = traverseList(a);
+
+console.log(arr[arr.length - 2]);