[LeetCode] 804. Unique Morse Code Words

[grandyang]

 

International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-", "b" maps to "-...", "c" maps to "-.-.", and so on.

For convenience, the full table for the 26 letters of the English alphabet is given below:

[".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]

Now, given a list of words, each word can be written as a concatenation of the Morse code of each letter. For example, "cab" can be written as "-.-.-....-", (which is the concatenation "-.-." + "-..." + ".-"). We'll call such a concatenation, the transformation of a word.

Return the number of different transformations among all words we have.

Example:
Input: words = ["gin", "zen", "gig", "msg"]
Output: 2
Explanation: 
The transformation of each word is:
"gin" -> "--...-."
"zen" -> "--...-."
"gig" -> "--...--."
"msg" -> "--...--."

There are 2 different transformations, "--...-." and "--...--.".

 

Note:

• The length of words will be at most 100.
• Each words[i] will have length in range [1, 12].
• words[i] will only consist of lowercase letters.

 

这道题说的就是大名鼎鼎的摩斯码了，给了我们所有字母的摩斯码的写法，然后给了我们一个单词数组，问我们表示这些单词的摩斯码有多少种。因为某些单词的摩斯码表示是相同的，比如gin和zen就是相同的。最简单直接的方法就是我们求出每一个单词的摩斯码，然后将其放入一个HashSet中，利用其去重复的特性，从而实现题目的要求，最终HashSet中元素的个数即为所求，参见代码如下：

 

class Solution {
public:
    int uniqueMorseRepresentations(vector<string>& words) {
        vector<string> morse{".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."};
        unordered_set<string> s;
        for (string word : words) {
            string t = "";
            for (char c : word) t += morse[c - 'a'];
            s.insert(t);
        }
        return s.size();
    }
};

 

讨论：这道题其实没有充分发挥其潜力，摩斯码的场景很好，只是作为一道Easy题未免有些可惜了。一个比较显而易见的follow up就是，给我们一个摩斯码，问其有几种可能的单词组，比如给我们一个"--...-."，那么我们知道至少有两种zen和gin，可能还有更多，这样是不是就更加有趣了呢？

 

类似题目：

https://leetcode.com/problems/unique-morse-code-words/solution/

https://leetcode.com/problems/unique-morse-code-words/discuss/120675/C++JavaPython-Easy-and-Concise-Solution

 

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