How do I deserialize a JSONArray?

[FaisalAbid]

Whats the best way to do this? The solution I found right now is pretty crappy?

 http.Response resp = await http.get('$endpoint');
List l = json.decode(resp.body);
    List<Message> c = new List();
    l.forEach((i){
      c.add(new Message.fromJson(i));
      return i;
    });

    return c;

[kevmoo]

import 'dart:convert';

main() async {
  var stuff;
  var myThing = (JSON.decode(stuff) as List).map((e) => new MyClass.fromJson(e)).toList();
}

[FaisalAbid]

Doesn't it make sense to have this method part of the library, so that you can pass in a Map or a List to fromJson?

It's just a lot of repeated code if you have a large api that returns JSONArrays for each of it's calls.

[kevmoo]

Agreed.

…

On Thu, Apr 12, 2018 at 7:52 AM Faisal Abid ***@***.***> wrote: Doesn't it make sense to have this method part of the library, so that you can pass in a Map or a List to fromJson? It's just a lot of repeated code if you have a large api that returns JSONArrays for each of it's calls. — You are receiving this because you modified the open/close state. Reply to this email directly, view it on GitHub <#135 (comment)>, or mute the thread <https://github.com/notifications/unsubscribe-auth/AABCikf7QPSyNpywb85PKJS5AUZj94VZks5tn2oQgaJpZM4TRE2Q> .

[FaisalAbid]

to add to that, does it also make sense to do a json.decode(). why not just pass the json string and let json_serializeable deal with it?

for example

MyClass c = new MyClass.fromJson(responsePayloadFromServer);

Neat and clean

[thiagosantoscunha]

You can serialize as follows:

List<Obj> (jsonDecode(value) as List).map((f) => Obj.fromJson(f)).toList();

I hope I helped because it seems that the serializations shown are out of date.