Not breaking at highest syntactic level

[bethcutler]

Original code:

val result = sequence(Person("alice", 25), Person("bob", 20), Person("charlie", 30))
  .ktMap("MapExtractName") { it.name }

Expected result after ktfmt:

val result = 
  sequence(Person("alice", 25), Person("bob", 20), Person("charlie", 30))
    .ktMap("MapExtractName") { it.name }

Actual result:

val result =
  sequence(Person("alice", 25), Person("bob", 20), Person("charlie", 30)).ktMap(
    "MapExtractName"
  ) { it.name }

[bethcutler]

A similar example, possibly related:

  val foo =
    aCall(withALongParameter).anotherChainedCall(withAnotherLongParameter).andAnother().arrayHere[
        100]
      .apply {
        // something
      }

[hick209]

v0.49 gets us this:

val result =
    sequence(Person("alice", 25), Person("bob", 20), Person("charlie", 30)).ktMap(
        "MapExtractName") {
          it.name
        }

val foo =
    aCall(withALongParameter)
        .anotherChainedCall(withAnotherLongParameter)
        .andAnother()
        .arrayHere[100]
        .apply {
          // something
        }

I still dislike the first one as it does not make things any clear.
I do think the second case is good though.