Print full directory name from lsof #3440
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awk splits lines based on spaces, which causes directory names with spaces to end up in other fields. Using a for loop allows us to print from the 9th field onwards instead of just the 9th field.
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| @@ -58,7 +58,7 @@ function getProcessCommand(processId, processDirectory) { | |||
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| function getDirectoryOfProcessById(processId) { | |||
| return execSync( | |||
| 'lsof -p ' + processId + ' | awk \'$4=="cwd" {print $9}\'', | |||
| 'lsof -p ' + processId + ' | awk \'$4=="cwd" {for (i=9; i<=NF; i++) printf "%s ", $i}\'', | |||
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(Unfortunately, a for loop appears to be the most efficient way to do this; the alternative is to set fields 1-8 to blank strings, but that'd end up less clear as to the intent.)
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I haven't tested but I trust you this works. |
awk splits lines based on spaces, which causes directory names with spaces to end up in other fields. Using a for loop allows us to print from the 9th field onwards instead of just the 9th field.
awk splits lines based on spaces, which causes directory names with spaces to end up in other fields. Using a for loop allows us to print from the 9th field onwards instead of just the 9th field.
Fixes #3439.