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# Instructions | ||
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Your task is to determine the date and time one gigasecond after a certain date. | ||
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A gigasecond is one thousand million seconds. | ||
That is a one with nine zeros after it. | ||
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If you were born on _January 24th, 2015 at 22:00 (10:00:00pm)_, then you would be a gigasecond old on _October 2nd, 2046 at 23:46:40 (11:46:40pm)_. |
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# Introduction | ||
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The way we measure time is kind of messy. | ||
We have 60 seconds in a minute, and 60 minutes in an hour. | ||
This comes from ancient Babylon, where they used 60 as the basis for their number system. | ||
We have 24 hours in a day, 7 days in a week, and how many days in a month? | ||
Well, for days in a month it depends not only on which month it is, but also on what type of calendar is used in the country you live in. | ||
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What if, instead, we only use seconds to express time intervals? | ||
Then we can use metric system prefixes for writing large numbers of seconds in more easily comprehensible quantities. | ||
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- A food recipe might explain that you need to let the brownies cook in the oven for two kiloseconds (that's two thousand seconds). | ||
- Perhaps you and your family would travel to somewhere exotic for two megaseconds (that's two million seconds). | ||
- And if you and your spouse were married for _a thousand million_ seconds, you would celebrate your one gigasecond anniversary. | ||
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~~~~exercism/note | ||
If we ever colonize Mars or some other planet, measuring time is going to get even messier. | ||
If someone says "year" do they mean a year on Earth or a year on Mars? | ||
The idea for this exercise came from the science fiction novel ["A Deepness in the Sky"][vinge-novel] by author Vernor Vinge. | ||
In it the author uses the metric system as the basis for time measurements. | ||
[vinge-novel]: https://www.tor.com/2017/08/03/science-fiction-with-something-for-everyone-a-deepness-in-the-sky-by-vernor-vinge/ | ||
~~~~ |
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{ | ||
"authors": [ | ||
"ErikSchierboom" | ||
], | ||
"files": { | ||
"solution": [ | ||
"src/gigasecond.cljs" | ||
], | ||
"test": [ | ||
"test/gigasecond_test.cljs" | ||
], | ||
"example": [ | ||
".meta/src/example.cljs" | ||
] | ||
}, | ||
"blurb": "Given a moment, determine the moment that would be after a gigasecond has passed.", | ||
"source": "Chapter 9 in Chris Pine's online Learn to Program tutorial.", | ||
"source_url": "https://pine.fm/LearnToProgram/?Chapter=09" | ||
} |
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(ns gigasecond) | ||
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;; Given a moment, compute the moment that would be after an arbitrary number | ||
;; of seconds has passed (one Gigasecond for this example). | ||
;; | ||
;; This function works is extreme cases like: | ||
;; * Periods of any size (any positive number of seconds) | ||
;; * Periods that include years like 1900 inside (oddly not leap year) | ||
;; * Periods that start (or end), before (or after), the end of February in | ||
;; years that are (or not) leap years | ||
;; * Periods that start (or end), before (or after), the start (or end) of any | ||
;; year | ||
;; | ||
;; Note: The number of seconds is embedded as `total-seconds` binding | ||
(defn from [y m d] | ||
;; Steps: | ||
;; 1) Convert time period to days | ||
;; 2) Compute result thru 3 sections of the period (Start, Middle, End) | ||
;; 2a) Start: Remaining days in first month of the period | ||
;; 2b) Middle: Find last month of the period (loop through months/years) | ||
;; 2c) End: Days in the last month of the period | ||
(letfn [;; Helper to compute boolean whether a year is leap or not | ||
(leap-year? [year] | ||
(cond | ||
(zero? (mod year 400)) true | ||
(zero? (mod year 100)) false | ||
:else (zero? (mod year 4)))) | ||
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;; Helper to compute total number of days in a year's month | ||
(days-in-month [year month] | ||
(cond | ||
(= month 2) (if (leap-year? year) 29 28) ; February | ||
(some #(= month %) [4 6 9 11]) 30 ; Abril, June, ... | ||
:else 31)) ; January, March, ... | ||
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;; Helper to compute the number of remaining days of a date's month | ||
;; Ex.: [2000 2 27] results in 3 days because 2000 is a leap year | ||
;; so day 27, day 28 and day 29 are 3 days in total. | ||
;; (To obtain the total days of a particular month, set day to 1) | ||
(days-to-next-month [year month day] | ||
(+ (days-in-month year month) (- day) 1))] | ||
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(let [total-seconds 1e9 ;; Gigasecond (works with any positive number) | ||
seconds-per-day 86400 ;; 24 x 60 x 60 | ||
;; Convert seconds to days | ||
total-days (int (/ total-seconds seconds-per-day))] | ||
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;; Loop thru months decrementing the the total days remaining in period | ||
(loop [;; Initialize date and total days in period | ||
year y | ||
month m | ||
day d | ||
remaining total-days] | ||
(let [;; Compute amount to jump according to distance to next month | ||
;; First loop cycle computes from date's day (step 2a) | ||
;; Following cycles compute from 1st of current month (step 2b) | ||
jump (days-to-next-month year month day)] | ||
;; Out of the loop when no more room for another month | ||
(if-not (>= remaining jump) | ||
;; Result (step 2c) | ||
[year month (+ day remaining)] | ||
;; Update to next month and increment year when necesary | ||
(recur ;; Increment year when December jumps to January | ||
(if (zero? (mod month 12)) (inc year) year) | ||
;; Circular month increment (December jumps to January) | ||
(inc (mod month 12)) | ||
1 ;; 1st of month | ||
;; Decrement the the total days remaining in period | ||
(- remaining jump)))))))) |
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# This is an auto-generated file. Regular comments will be removed when this | ||
# file is regenerated. Regenerating will not touch any manually added keys, | ||
# so comments can be added in a "comment" key. | ||
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[92fbe71c-ea52-4fac-bd77-be38023cacf7] | ||
description = "date only specification of time" | ||
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[6d86dd16-6f7a-47be-9e58-bb9fb2ae1433] | ||
description = "second test for date only specification of time" | ||
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[77eb8502-2bca-4d92-89d9-7b39ace28dd5] | ||
description = "third test for date only specification of time" | ||
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[c9d89a7d-06f8-4e28-a305-64f1b2abc693] | ||
description = "full time specified" | ||
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[09d4e30e-728a-4b52-9005-be44a58d9eba] | ||
description = "full time with day roll-over" |
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{:deps | ||
{org.clojure/clojure {:mvn/version "1.10.1"} | ||
org.clojure/clojurescript {:mvn/version "1.10.773"}} | ||
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:aliases | ||
{:test | ||
{:extra-paths ["test"] | ||
:extra-deps | ||
{olical/cljs-test-runner {:mvn/version "3.8.0"}} | ||
:main-opts ["-m" "cljs-test-runner.main"]}}} |
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(ns gigasecond) | ||
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(defn from [] ;; <- arglist goes here | ||
;; your code goes here | ||
) |
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(ns gigasecond-test | ||
(:require [clojure.test :refer [deftest is]] | ||
gigasecond)) | ||
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(deftest from-apr-25-2011 | ||
(is (= [2043 1 1] (gigasecond/from 2011 4 25)))) | ||
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(deftest from-jun-13-1977 | ||
(is (= [2009 2 19] (gigasecond/from 1977 6 13)))) | ||
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(deftest from-jul-19-1959 | ||
(is (= [1991 3 27] (gigasecond/from 1959 7 19)))) | ||
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;; customize this to test your birthday and find your gigasecond date: | ||
;; (deftest your-birthday | ||
;; (is (= [year2 month2 day2] (gigasecond/from year1 month1 day1)))) |