The challenge is to determine the number of words that remain in the Russian/English (or any other language) language dictionary after removing all anagrams and subanagrams. The russian dictionary contains over 1.5 million words in various forms.
The proposed solution involves the use of a Trie data structure to efficiently search for anagrams and subanagrams in the dictionary. The Trie is constructed by adding each word to the tree, where each node contains a letter and its count in the word. Nodes are sorted alphabetically and by letter frequency in the word.
Algorithm (simplified):
- Add the dictionary to a Trie data structure.
- For each word in the dictionary, search for nodes starting with the minimum letter of the word.
- Once a matching node is found, traverse the subtree to check if the remaining letters exist in the required quantity.
- Advantage of Trie: Quick exit from the subtree if the node's letter is greater than the searched letter.
Consider a dictionary with five tricky words: ракета, карета, арка, кот, мокрота.
- Add the words to the Trie.
- For the word "кот," search for nodes starting with "к" in the Trie.
- Find nodes with "о-2" and "т-1" below the "к-1" node, satisfying the conditions for the word "кот."
Execute the following command to print all words remaining in the dictionary after eliminating anagrams and subanagrams:
./gradlew run