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This repository has been archived by the owner on Aug 15, 2024. It is now read-only.
This repository has been archived by the owner on Aug 15, 2024. It is now read-only.

Question: how come function references on the global scope are not closed #57

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@bradzacher

Description

describe("When there is a `function` declaration on global,", () => {
it("the reference on global should NOT be resolved.", () => {
const ast = espree(`
function a() {}
a();
`);
const scopeManager = analyze(ast, { ecmaVersion: 6 });
expect(scopeManager.scopes).to.have.length(2); // [global, a]
const scope = scopeManager.scopes[0];
expect(scope.variables).to.have.length(1);
expect(scope.references).to.have.length(1);
const reference = scope.references[0];
expect(reference.from).to.equal(scope);
expect(reference.identifier.name).to.equal("a");
expect(reference.resolved).to.be.null;
expect(reference.writeExpr).to.be.undefined;
expect(reference.isWrite()).to.be.false;
expect(reference.isRead()).to.be.true;
});
it("the reference in functions should NOT be resolved.", () => {
const ast = espree(`
function a() {}
function foo() {
let b = a();
}
`);
const scopeManager = analyze(ast, { ecmaVersion: 6 });
expect(scopeManager.scopes).to.have.length(3); // [global, a, foo]
const scope = scopeManager.scopes[2];
expect(scope.variables).to.have.length(2); // [arguments, b]
expect(scope.references).to.have.length(2); // [b, a]
const reference = scope.references[1];
expect(reference.from).to.equal(scope);
expect(reference.identifier.name).to.equal("a");
expect(reference.resolved).to.be.null;
expect(reference.writeExpr).to.be.undefined;
expect(reference.isWrite()).to.be.false;
expect(reference.isRead()).to.be.true;
});
});

I'm working on trying to understand this codebase better.
But I can't understand why it works this way:

function a() {}
a();

To me it seems clear that the reference that's created as part of the call should resolve directly to the function declaration, but it's not - it remains as an unresolved reference that's added to the global scope's through list.

This would cause the no-unused-vars ESLint rule to error on the function declaration, were it not for this code in the linter.

It looks like it works seemingly by chance? ESLint augments the global scope with more variables, and then forcefully resolves any through references against the global variable set, which includes the function declaration as well as the augmented variables.

Is anyone able to explain why this works this way?

Or a better question - when closing the global scope, why doesn't it attempt to resolve all through references against the variables defined in the global scope?

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