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1616 },
1717 {
18- "cell_type" : " code" ,
19- "execution_count" : null ,
20- "id" : " e4615d78-9088-47de-ab90-97ea4749e764" ,
18+ "cell_type" : " markdown" ,
19+ "id" : " a9339760-cf1c-4872-8129-0284f6c20d71" ,
2120 "metadata" : {},
22- "outputs" : [],
23- "source" : []
21+ "source" : [
22+ " ---\n " ,
23+ " \n " ,
24+ " ### **Solution**\n " ,
25+ " \n " ,
26+ " A rational function is discontinuous where its denominator is zero.\n " ,
27+ " \n " ,
28+ " **Find where the denominator is zero:**\n " ,
29+ " Set the denominator equal to zero:\n " ,
30+ " $$7 - e^{2x+3} = 0$$\n " ,
31+ " \n " ,
32+ " Solve for the exponential term:\n " ,
33+ " $$e^{2x+3} = 7$$\n " ,
34+ " \n " ,
35+ " **Solve for $x$:**\n " ,
36+ " Take the natural logarithm of both sides:\n " ,
37+ " $$2x + 3 = \\ ln(7)$$\n " ,
38+ " $$2x = \\ ln(7) - 3$$\n " ,
39+ " $$x = \\ frac{\\ ln(7) - 3}{2}$$\n " ,
40+ " \n " ,
41+ " **Conclusion:**\n " ,
42+ " The function $h(x)$ is discontinuous at $x = \\ frac{\\ ln(7) - 3}{2}$."
43+ ]
2444 }
2545 ],
2646 "metadata" : {
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