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LeetCode: 108 solved
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# https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/
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# Definition for a binary tree node.
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class TreeNode:
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def __init__(self, val=0, left=None, right=None):
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self.val = val
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self.left = left
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self.right = right
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class Solution:
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def sortedArrayToBST(self, nums: [int]) -> TreeNode:
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return self.iterate(nums, 0, len(nums) - 1)
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# Time O(n), Space O(n) for a tree.
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def iterate(self, nums, l, r):
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if l > r:
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return None
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m = l + (r - l) // 2
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left = self.iterate(nums, l, m - 1)
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right = self.iterate(nums, m + 1, r)
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return TreeNode(nums[m], left, right)
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