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_259.java
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package com.fishercoder.solutions;
import java.util.Arrays;
/**259. 3Sum Smaller
Given an array of n integers nums and a target, find the number of index triplets i, j, k with 0 <= i < j < k < n that satisfy the condition nums[i] + nums[j] + nums[k] < target.
For example, given nums = [-2, 0, 1, 3], and target = 2.
Return 2. Because there are two triplets which sums are less than 2:
[-2, 0, 1]
[-2, 0, 3]
Follow up:
Could you solve it in O(n2) runtime? */
public class _259 {
/**Basically, very similar to 3Sum, but the key is that you'll have to add result by (right-left), not just increment result by 1!*/
public int threeSumSmaller(int[] nums, int target) {
if (nums == null || nums.length == 0) {
return 0;
}
int result = 0;
Arrays.sort(nums);
for (int i = 0; i < nums.length - 2; i++) {
int left = i + 1;
int right = nums.length - 1;
while (left < right) {
int sum = nums[i] + nums[left] + nums[right];
if (sum < target) {
result += right - left;//this line is key!
left++;
} else {
right--;
}
}
}
return result;
}
}